Answer:
x = 1.4 (or 21/15)
Step-by-step explanation:
12x - 15 = 6 - 3x
+3x +3x
-----------------------
15x - 15 = 6
+15 +15
-----------------------
15x = 21
/15 /15
----------------------
x = 21/15 or
x = 1.4
Answer:
C
Step-by-step explanation:
Here in this question , we are interested in calculating the total distance covered by the train in the 10 minutes that it ran.
From the first part of the question, we already know the distances in the first 5 minutes.
Now, to calculate the total distance in the second 5 minutes, we use the distance formula since we have the average speed and the time;
Mathematically; Total distance = average speed * time
From the question, average speed is 33km/h, while time is 5 minutes. To achieve a consistent unit, we convert 5 minutes to hours.
That would be 5/60 = 1/12 hours
So the total distance in the second 5 minutes is;
33 * 1/12 = 2.75 km
Now, to calculate the total distance traveled, let’s add up the distances in the first 5 minutes and convert to kilometers;
That would be;
68 + 127 + 208 + 312 + 535 = 1,250 m
Let’s convert this to km.
We simply divide by 1000 = 1250/1000 = 1.25 km
The total distance is thus ;
1.25 + 2.75 = 4 km
Answer:
boys = 250
girls = 150
Step-by-step explanation:
5g = 3b eq. 1
g + b = 400 eq. 2
g = girls
b = boys
From the eq. 2
g = 400 - b
Replacing this last eq. on eq. 1:
5(400-b) = 3b
5*400 + 5*-b = 3b
2000 - 5b = 3b
2000 = 3b + 5b
2000 = 8b
2000/8 = b
250 = b
From eq. 2
g + 250 = 400
g = 400 - 250
g = 150
Check:
from eq. 1
5*150 = 3*250 = 750
7x . h . 2xm
You can put together 6x and x
but since h, and 2xm arent alike terms, you cant combine
Answer:
eccentricity; e = 1/7
k = 12
Conic section; Ellipse
Step-by-step explanation:
The first step would be to write the polar equation of the conic section in standard form by multiplying the numerator and denominator by 1/7;

The polar equation of the conic section is now in standard form;
The eccentricity is given by the coefficient of cos theta in which case this would be the value 1/7. Therefore, the eccentricity of this conic section is 1/7.
The eccentricity is clearly between 0 and 1, implying that the conic section is an Ellipse.
The value in the numerator gives the value of k; k = 12