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Yuri [45]
3 years ago
7

4(a+2)=8+4a What is the value of a

Mathematics
1 answer:
madreJ [45]3 years ago
7 0

Answer:

there is no answer they are equal. anything can be put into a and it will still be true

Step-by-step explanation:

4a+8=8+4a

there is no answer

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Hello can anyone help me please
Naya [18.7K]

Answer:

5.3 to the 4th power :)

Step-by-step explanation:

7 0
3 years ago
Find the volume of the rectangular prism.<br> The volume is cm?<br><br> 8 cm<br> 5 cm<br> 9 cm
dedylja [7]

Answer:

360 cm

Step-by-step explanation:

volume= length x width x height

8*5*9=360 cm

6 0
3 years ago
Read 2 more answers
Two equations are listed below. Solve each equation and compare the solutions. Choose the statement that is true about both solu
enyata [817]
<span>|5x − 6| = −41  it has no solutions because module ( abs value) cannot be negative

|7x + 13| = 27          -(7x+13)=27
7x+13=27                 -7x-13=27
7x=14                       -7x=40
x=2                            x=-40/7

check:   </span>|7*(-40/7) + 13| = 27  ,   |-40 + 13| = 27,   |-27| = 27 correct<span>
                               
There are no statements, so I cannot choose the correct one</span>
8 0
3 years ago
A rose garden is formed by joining a rectangle and a semicircle, as shown below. The rectangle is 24 ft long and 14 ft wide.
expeople1 [14]

rounded part is a semicircle so the area for that is the area of a circle ÷ 2

so

area of the rectangle + (area of the circle ÷ 2) = answer

24 * 14 = 336 = area of the rectangle

14 ÷ 2 = r

(pi * 7^2) ÷ 2

(pi * 49) ÷ 2 = 153.86 ÷ 2 = 76.93 = area of semicircle

336 + 76.93 = 412.93 ft^2 = answer

6 0
3 years ago
Law of sines?? side c=22 side a=16 side b= 21 solve for angle c??? help
den301095 [7]

Answer:

Angle C measures:  71.52^o

Step-by-step explanation:

When you know the length of the three sides of the triangle and not a single angle, the law of sines is of no use. You need to use the law of cosines. In your case, since you want to find angle "C", you use the following;

c^2=a^2+b^2-2\,a\,b\,cos(C)\\2\,a\,b\,cos(C)=a^2+b^2-c^2\\cos(C)=\frac{a^2+b^2-c^2}{2\,a\,b} \\cos(C)=\frac{16^2+21^2-22^2}{2\,(16)\,(21)}\\cos(C)=0.3169643\\C=arccos(0.3169643)\\C=71.52^o

4 0
4 years ago
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