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Yuri [45]
3 years ago
7

4(a+2)=8+4a What is the value of a

Mathematics
1 answer:
madreJ [45]3 years ago
7 0

Answer:

there is no answer they are equal. anything can be put into a and it will still be true

Step-by-step explanation:

4a+8=8+4a

there is no answer

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Find the value of x in the equilateral triangle.<br> Х<br> 3 in
swat32

Answer:

x≈3.35, or the square root of 11.

Step-by-step explanation:

Use the pythagorian therom. 3²+1.5²=x²

(Half of 3 is 1.5 and the line splits it in half)

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Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
2 years ago
What is the y-intercept in the equation y=8x+6
lisabon 2012 [21]

Answer:

(0,6) or 6

Step-by-step explanation:

To find the y-intercept look at the last variable you have, which in this case is 6. Glad to help :)

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