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3 years ago

I need help please ))):

Mathematics

2 answers:

Travka [436]3 years ago

6 0

The answer is 2

Hope I helped

tekilochka [14]3 years ago

3 0

the answer is 2.

(ignore this)

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The data below show the weights, in pounds, of a group of professional football players.

monitta

Answer:

The Mean Absolute Deviation is 11

Step-by-step explanation:

Given:

325, 310, 289, 288, 285, 285, 285, 280, 280 and 273

Mean = 290

Required:

Calculate the Mean Absolute Deviation

Provided that we have the value of the mean to be 290 from the question; the following steps will calculate the Mean Absolute Deviation

Step 1: Subtract the mean weight from each weight

325 - 290 = 35

310 - 290 = 20

289 - 290 = -1

288 - 290 = -2

285 - 290 = -5

280 - 290 = -10

273 - 290 = -17

Step 2: Calculate the absolute value of the each results above

|35| = 35

|20| = 20

|-1| = 1

|-2| = 2

|-5| = 5

|-10| = 10

|-17| = 17

Step 3: Calculate the mean of the data above

Mean Absolute Value = $\frac{35 + 20 + 1 + 2 + 5 + 5 + 5 + 10 + 10 + 17}{10}$

Mean Absolute Value = $\frac{110}{10}$

Mean Absolute Value = 11

Hence, the Mean Absolute Deviation is 11

3 0

3 years ago

Identify the Terms, Constants, Coefficients and Variables in the following eqaution:

irinina [24]

Answer:

<h2>13x - 1. Term</h2><h2>5y - 1. Term</h2><h2>13 - 3. Coefficient</h2><h2>2 - 2. Constant</h2><h2>5 - 3. Coefficient</h2><h2>y - 4. Variable</h2><h2>3 - 2. Constant</h2><h2>x - 4. Variable</h2>

Step-by-step explanation:

<h3>13x + 5y - 2 = 3</h3><h3 /><h3><u>Term</u> has a <em>number and also a variable</em>. </h3><h3>Ex.: 5y</h3><h3 /><h3><u>Constant</u> is any <em>number without a variable</em>.</h3><h3>Ex.: 3</h3><h3 /><h3><u>Coefficient</u> is the <em>number in a term</em>.</h3><h3>Ex.: 13</h3><h3 /><h3><u>Variable</u> is any <em>letter</em> in the equation.</h3><h3>Ex.: x</h3><h3 />

$\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}$