Answer:
We conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
Step-by-step explanation:
We know that the perimeter of a rectangle = 2(l+w)
i.e.
P = 2(l+w)
Here
Given that the length and width of the playground by a scale factor of 2
A scale factor of 2 means we need to multiply both length and width by 2.
i.e
P = 2× 2(l+w)
P' = 2 (2(l+w))
= 2P ∵ P = 2(l+w)
Therefore, we conclude that If Tawnee increases the length and width of the playground by a scale factor of 2, the perimeter of the new playground will be twice the perimeter of the original playground.
4 2/9=8/9
8/9 x 6=48/9= 5 3/9
5 3/9= 5 1/3
440- 2x= 244 // simplify the equation given
I got 784 inches cubed, I cut the figure into two, the first one was 8×4×14=448, the second was 8×3×14=336,
therefore 448+336=784
Answer:
7.5 short tons
Step-by-step explanation:
16 3/10 - 8 4/5 = 7.5
