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3 years ago

It is 8 kilometers from Lucy's house to the nearest mailbox. How far is it in meters?

Mathematics

1 answer:

allochka39001 [22]3 years ago

3 0

Answer:

8000

Step-by-step explanation:

multiply the length value by 1000

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black pencils cost 75 naira each and colour pencils cost 105 naira each if 24 mixed pencils cost 2010 naira how many of them wer

KonstantinChe [14]

Answer:

number of black pencils is 17

7 0

3 years ago

I WILL GIVE BRAINLIEST Given: BFCE, AB perpendicular to BE, DE perpendicular to BE,

mars1129 [50]

Answer:

Step-by-step explanation:

From the given picture,

∠ABE = ∠DEF = 90° [Since, AB and DE are perpendicular to DE]

m∠ECA = m∠BFD [Given]

m∠ECA + m∠ACB = 180° [Liner pair of angles]

m∠BFD + m∠DFE = 180° [Liner pair of angles]

m∠ACB + m∠ECA = m∠BFD + m∠DFE [Transitive property]

m∠ACB = m∠DEF [Since, m∠ECA = m∠BFD]

Therefore, ΔABC ≅ ΔDEF [By AA property of similarity]

3 0

2 years ago

1 and 2 are a linear pair, and 2 and 3 are vertical angles. m 2=(5+4 y) and m 3=(6 y-25). what is m 1

poizon [28]

Vertical angles are equal to each other:
    ∠2    =    ∠3
   5 + 4y = 6y - 25
→ 30 = 2y
→    15 = y

∠2 = 5 + 4y = 5 + 4(15) = 5 + 60 = 65

linear pairs equal 180:
   ∠1 + ∠2 = 180
→ ∠1 + 65 = 180
→ ∠1 = 115

5 0

3 years ago

8 cm<br> 6 cm<br> 2 cm<br> Find the surface area of the rectangular prism.<br> Surface Area = [?]cm²

SashulF [63]

Answer:

152cm²

Step-by-step explanation:

math and stuff and things

5 0

2 years ago

Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees

lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e. $\mu=0$ and $\sigma= 1$

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

$P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035$

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

8 0

3 years ago