7/8(x-1/2)= -49/80
Multiply the bracket by 7/8
7/8x-7/16= -49/80
Move -7/16 to other side. Sign changes from -7/16 to +7/16
7/8x-7/16+7/16= -49/80+7/16
7/8x= -49/80+7/16
Find common denominator for 7/16 which is 5. Multiply 5 for the numerator and denominator.
7(5) / 16 (5)
= 35/80
7/8x= -49/80+35/80
7/8x= -14/80
Reduce -14/80 , divide by 2
(-14) /2=7 , 80/2= 40
-14/80= -7/40
7/8x= -7/40
Multiply by 8/7
7/8x*8/7= -7/40 * 8/7
Cross out 7 and 7 , and divide by 7. Cross out -7 and 7 and divide by 7. Cross out 40 and 8 divide by 8.
x= -1/5
Answer: x= -1/5 - G.
The volume of a sphere is calculated like so:
v = 4*pi*r^3/3
so half sphere will have half that volume:
v = (<span>4*pi*r^3/3)(1/2)
</span>v = <span>4*pi*r^3/6
</span>plug in the data:
v = <span>4*pi*(10)^3/6
</span>v = 2094.4
that is the volume of the half sphere
The answer is (C) because you multiply each point by 1.5.
Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:

The amount of deer that were initally in the reserve corresponds to the value of N when t=0


A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
<span>Find the equation of the line parallel to the line y = 4x – 2 that passes through the point (–1, 5).
</span>y = 4x – 2 has slope = 4
<span>parallel lines have same slope so slope = 4
</span><span>passes through the point (–1, 5).
</span><span>y = mx+b
5 = 4(-1) + b
b =9
equation
y = 4x + 9
answer
The slope of y = 4x – 2 is 4
The slope of a line parallel to y = 4x – 2 is 4
The equation of the line parallel to y = 4x – 2 that passes through the point (–1, 5) is y = 4x + 9</span>