I'm grade 6 I don't know ................
Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
You use the rule , y2-y1/x2-x1 , to find the slope so the answer will be = 0-2/4-1 = -2/3
Answer:
balloons= 9
candles= 8
Step-by-step explanation:
let the number of balloons be x
and candles be y
So
15x+8y=192----------1
x+y=17--------------2
from 2, x= 17-y
put x= 17-y in 1
15( 17-y)+8y=192
255-15y+8y=192
solve for y
-7y=192-255
-7y=-63
x=63/7
x=9
put x= 9 in 1
9+y=17
y= 17-9
y=8.

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction
8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})
goes to

now we can simplify the multiplied terms

Now that we have common bases, we can add the 2 fractions together to get
