This is a cross-sectional view of candy bar ABC. A candy company wants to create a cylindrical container for candy bar ABC so th
at it is circumscribed about the candy bar. If segment AD = 4 cm, what is the smallest diameter of wrapper that will fit the candy bar? Triangle ABC in which point E is between points A and B, point D is between points A and C, point F is between points B and C, segments AE and EB are congruent, segments BF and FC are congruent, and angles AED, ABF, and DFC are right angles.
1 answer:
Answer:
8 cm
Step-by-step explanation:
When a right triangle is circumscribed in a circle, the diameter is the hypotenuse AC.
Therefore, the smallest diameter of the wrapper will be that of the circle whose diameter has endpoints of A and C.
From the diagram:
- AE=DF
- ED=FC
Therefore, Triangle AED is congruent to Triangle DFC and in fact AD=DC.
Given: AD =4 cm
Therefore, the smallest diameter
AC=AD+DC
=4+4
=8 cm
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