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Marizza181 [45]
3 years ago
11

A bacterial culture grows exponentially according to the function n(t)=n(e^n), where n(t) is the quantity after t hours and n is

the original quantity. If the culture grows from 2 grams to 128 grams in 3 hours, how many grams where there after 2 hours?
Mathematics
1 answer:
mart [117]3 years ago
5 0

Answer:

n(t=2) = 2 e^{1.386294361(2)}=32 grams

So then after 2 hours we will have 32 grams.

Step-by-step explanation:

For this case we have the followin exponential model:

n(t) = n e^{rt}

n(t) is the quantity after t hours, n is the original quantityand t represent the hours and r the rate constant.

For this case we know that n(0) = 2 grams and n(3) = 128 grams and we want to find n(2)=?

From the initial condition we know that n = 2, and we have the model like this:

n(t) = 2 e^{rt}

Now if we apply the other conditionn(3) = 128 we got:

128 = 2 e^{3r}

If we divide both sides by 2 we got:

64= e^{3r}

If we apply natural log for both sides we got:

ln(64) = 3r

r = \frac{ln(64)}{3}=1.386294361

And our model is this one:

n(t) = 2 e^{1.386294361t}

And if we replace t = 2 hours we got:

n(t=2) = 2 e^{1.386294361(2)}=32 grams

So then after 2 hours we will have 32 grams.

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Frank has 24 pennies, 62 nickels, 55 dimes, 16 quarters, and 19 fifty-cent pieces. How much money does he have?
DedPeter [7]

Answer:

$22.34

Step-by-step explanation:

really simple.

just multiply the number by how much the coin is worth

24 x 1 = 24

62 x 5 = 310

55 x 10 = 550

16 x 25 = 400

19 x 50 = 950

then add all of them

24 + 310 + 550 + 400 + 950 = 2234

and finally divide it by 100

2234 ÷ 100 = 22.34

and just pop in a dollar sign

$22.34

8 0
3 years ago
The height of a toy rocket that is shot in the air with an upward velocity of 48 feet per second can be modeled by the function
NikAS [45]

Answer:

maximum height reached = 35 feet

and f(t) = 48t-16.07t^{2}

Step-by-step explanation:

writing linear motion equations

s = ut + \frac{1}{2}at^{2}

where s is the total displacement, u the initial velocity, t the time travelled, and a is the acceleration.

given u = 48 ft/s, and a = acceleration due to gravity g = -9.8\frac{m}{s^{2}}

1 m = 3.28 feet therefore g becomes -9.8×3.28\frac{ft}{s^{2}}

here negative sigh comes as acceleration due to gravity is in opposite direction of initial velocity.

therefore f(t) becomes f(t) = 48t-16.07t^{2}

to find max height we should find differentiation of f(t) and equate it to 0

therefore we get 48 = 32.144t

t = 1.49 s

therefore max height f(1.49) = 71.67-36.67 = 35 feet

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