Answer:
Last answer.
Step-by-step explanation:
What I do is divide the terms by the previous terms, and if they all equal 1.5, that is your answer.
There are only two possible outcomes in the table that satisfy <em>x</em> ≤ -3; either <em>x</em> = -5 or <em>x</em> = -3. Then
P(<em>x</em> ≤ -3) = P(<em>x</em> = -5) + P(<em>x</em> = -3) = 0.17 + 0.13 = 0.3
Answer:
$2355.06
Step-by-step explanation:
Use the compound interest formula, filling in the numbers you know. Then solve for the number you don't know.
A = P(1 +r/n)^(nt)
where A is the account balance, P is the amount invested, r is the annual rate, n is the number of times per year interest is compounded, and t is the number of years.
Filling in the given values, we have ...
4000 = P(1 +.053/52)^(52·10) = P(1.6984738)
P = 4000/1.6984738 ≈ 2355.06
You would need to deposit $2355.06 in order to have $4000 in 10 years.
Answer:
Step-by-step explanation:
2{5x²-15+(-9xy²)}-(2y²+4x-xy²)+3x²
=2{5x²-15-9xy²}-(2y²+4x-xy²)+3x²
=10x²-30-18xy²-2y²-4x+xy²+3x²
=13x²-2y²-17xy²-4x-30
I think it is 3.6 .......
