I believe the mean is 60 pounds
Answer:
1 pound = 0.454 kilograms
1 ounce = 0.0296 liters
1 ounce = 0.0283 kilograms
Step-by-step explanation:
You need to convert the quantities to their corresponding unit.
Convert pounds to kilograms (For the entrecote)
1 pound = 0.454 kilograms
Thus, 1 pound of entrecote = 0.454 kilograms
Ounces to liters (for the Béarnaise, since it is a liquid)
1 ounce = 0.0296 liters
2 ounces of Béarnaise = 0.0592 liters
Ounces to kilograms (for the asparagus)
1 ounce = 0.0283 kilograms
4 ounces of asparagus =0.1132 kilograms
Paralell to x=c1 is x=c2 where c1 and c2 are constants
for x=2, passing through (-1,-5), that is (x,y)
x=-1 is the line
Ok so pete lays 10 more than jim per hour
pete and jim laid same amount of tiles
j=jim's rate
p=pete's rate
6j=5p
but pete lays 10 tile per hour faster so
p=10+j
sub
6j=5(10+j)
6j=50+5j
minus 5j both sides
j=50
jim can lay at 50 tiles per hour
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.