What is the slope of the line that contains the points (5, –9) and (5, 9)?

Mathematics

2 answers:

Yakvenalex [24]3 years ago

6 0

It would be: (y2-y1) / (x2-x1) = (9-(-9)/5-5 = 18/0 = undefined

OPTION D IS YOUR ANSWER.........

Evgesh-ka [11]3 years ago

4 0

Slope(m)=(y2-y1)/(x2-x1)
here
(5,-9)=(x1,y1)
(5,9)=(x2,y2)
so, m= (9+9)/(5-5)=infinity
it means the line is perpendicular with the x-axis
because tan90 is equal to infinity
so in order to make slope infinity the line should make 90 angle with positive x axis

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HELP ME PLEASE!!!

ser-zykov [4K]

parallel lines, have the same exact slope, hmmm what is the slope of y = -2/3 x + 1/3 anyway? well, low and behold, the equation is already in slope-intercept form, therefore

$\bf ~~y=\stackrel{slope}{-\cfrac{2}{3}}x+\cfrac{1}{3}~~$ has a slope of -2/3.

so we're really looking for a line whose slope is -2/3 and runs through 9,4.

$\bf (\stackrel{x_1}{9}~,~\stackrel{y_1}{4})~\hspace{10em}slope = m\implies -\cfrac{2}{3}\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{2}{3}(x-9)\\\\\\y-4=-\cfrac{2}{3}x+6\implies y=-\cfrac{2}{3}x+10$