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anzhelika [568]
3 years ago
14

20. Find the midpoint between the given points.

Mathematics
1 answer:
AlexFokin [52]3 years ago
5 0

Hi there! :)

Answer:

\huge\boxed{(-1, -10.5)}

Use the midpoint formula to solve for the midpoint:

(x_{m}, y_{m}) = (\frac{x_{1}+x_{2} }{2} , \frac{y_{1}+y_{2}}{2})

Plug in the points:

(x_{m}, y_{m}) = (\frac{-5+3 }{2} , \frac{-13 -8}{2})

Simplify:

(x_{m}, y_{m}) = (\frac{-2 }{2} , \frac{-21}{2})

(x_{m}, y_{m}) = (-1 , -10.5)

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Simplify by dividing negative three over eight ÷ five over nine . (5 points)
Marysya12 [62]

Answer:

A.) negative twenty-seven over forty

Step-by-step explanation:

Screenshot below will explain the answer

8 0
3 years ago
Solve using perfect square factoring patterns. y2 + 14y + 49 = 0
Studentka2010 [4]
(y + 7)(y + 7)

49 is a perfect square of 7

it can also be written

(y + 7)²

hope this helps :)


7 0
3 years ago
What conclusion can you make about you negative number raised to an odd power
Ahat [919]
The answer is negative
7 0
3 years ago
Triangle PQR has vertices at the following coordinates: P(0, 1), Q(3, 2), and R(5, -4). Determine whether or not triangle PQR is
ruslelena [56]
PQ =  \sqrt{(3-0)^2+(2-1)^2}= \sqrt{9+1}= \sqrt{10}    \\ QR= \sqrt{(5-3)^2+(-4-2)^2}= \sqrt{4+36}= \sqrt{40} \\PR= \sqrt{(5-0)^2+(-4-1)^2}= \sqrt{25+25}= \sqrt{50}

PR is the longest side.
The triangle will be right if
PQ² + QR² = PR²

PQ² + QR² = (√10)² + (√40)² = 10 + 40 = 50
PR² = (√50)² = 50
50=50  so, ΔPQR is <span>a right triangle.</span>
8 0
3 years ago
Read 2 more answers
2 people are going to share 5kg of chocolate. How many kilograms of chocolate should each person get
jasenka [17]

Answer:

2.5 kg per person

Step-by-step explanation:

Take the amount of chocolate and divide by the number of people

5 kg /2

2.5 kg per person

5 0
4 years ago
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