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Art [367]
3 years ago
9

How can you determine which variable is dependent and which variable is independent

Mathematics
2 answers:
padilas [110]3 years ago
8 0

MrBillDoesMath!

Answer:  The dependent variable depends on another variable for its value. For example, if  y = 2x,  setting x = 1 forces y= 2.; setting x = 10, forces y =20.  There are no other possibilities for y once x ids chosen. So y is the dependent variable and x is the independent one. You can pick values for the independent variable (x) but no so for the dependent one.

MrB

kari74 [83]3 years ago
8 0

This is actually quite a deep-going question. To truly determine which variables (in an experiment, or in an observation of nature) depend of other variables is sometime very difficult and laborious. In math this may be easier. See detail below.

In pure mathematics, where variables do not necessarily carry a physical meaning, the determination is a matter of definition. A variable is defined to be dependent on another variable, for instance, y depends on x via the specific function, y = 10x + 10. The key is: this is given. Otherwise (if it were not given), suppose I gave you an equation a+b=10 and not told you which is the dependent and which the independent variable. You could think of each being either: a=10-b and b=10-a. Without this being defined, there is no clear way to determine dependency.  

In science, on the other hand, the determination is made based on experimental design and based on certain plausible assumptions about natural dependencies. For example, if you design an experiment to measure some physical quantity, such a height of an individual, you can look at the that as a variable dependent on other variables, such as age, ie., what is the average height of a person given their particular age (say, 0, 1, 2,..., 18 years of age). It would be more of a stretch to measure the age as dependent variable of height.

I hope these thoughts are helpful.

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How to simply the radical
zlopas [31]
6√2 + 4 √32
try to get the same number "2" remaining under the root sign by finding what # times 2 gives 32
6√2 + 4√2×√16
since 16 is a perfect Square √16 gives 4
therefore.
6√2 + 4 ×4 √2
6√2 +16√2
these are Like terms so add them
which would give u
22√2
hoped i helped, feel free to ask any question XOX
3 0
3 years ago
I'll give brainiest what is √(4²+6²)=√52=2√13 rounded to the nearest tenth in decimal form
Contact [7]

Answer:

7.2

Step-by-step explanation:

6 0
3 years ago
100 pts. & will give brainliest! answer asap
Zanzabum

First we need to differentiate y

\\ \sf\Rrightarrow \dfrac{dy}{dx}

\\ \sf\Rrightarrow \dfrac{d}{dx}(-16x^2-110x+15)

\\ \sf\Rrightarrow -32x-110

Now let it be 0

\\ \sf\Rrightarrow -32x-110=0

\\ \sf\Rrightarrow -32x=110

\\ \sf\Rrightarrow x=|110/-32

\\ \sf\Rrightarrow x=3.44s

Put it in y

\\ \sf\Rrightarrow y=15-110(3.44)-16(3.44)^2

\\ \sf\Rrightarrow y=204.05ft

3 0
3 years ago
How do I do this??????? 2/3x-(1/2x+1)<br>btw need it simplified
Setler79 [48]

Answer:

  1/6x -1

Step-by-step explanation:

"Simplify" generally means, "eliminate parentheses and combine like terms." In general, parentheses are eliminated by making use of the distributive property.

__

  \dfrac{2}{3}x-\left(\dfrac{1}{2}x+1\right)=\dfrac{2}{3}x-\dfrac{1}{2}x-1=\left(\dfrac{2}{3}-\dfrac{1}{2}\right)x-1\\\\=\left(\dfrac{4}{6}-\dfrac{3}{6}\right)x-1=\boxed{\dfrac{1}{6}x-1}

5 0
2 years ago
The table shows some information about the lifetimes,
NISA [10]

Answer:

25 < t < 350

Step-by-step explanation:

The mean lifetime of a bulb ranges from 25 to 350 hrs but the question is unclear.

8 0
2 years ago
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