De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
Answer:
-3/5
Step-by-step explanation:
to figure that out you have to do y^2 - y^1/ x^2 - x^1
2-(-1)/ -3 - 2
= 3/-5
=-3/5
Answer:
the volume is 15.7 in. 3............
Answer:
8={8,16,24,32,40}
6={6,12,18,24,33}
so the least common multiple is 24
Answer:
the second one
Step-by-step explanation:
y = 2/3 (x +6)-5
