For the definition of <em>horizontal</em> compression, the function f(x) = x² is horizontally compressed to the function g(x) = (k · x)², for 0 < k < 1.
<h3>How to find the resulting equation after applying a compression</h3>
Here we must narrow a given function by a <em>rigid</em> operation known as compression. <em>Rigid</em> transformations are transformations in which <em>Euclidean</em> distances are conserved. In the case of functions, we define the horizontal compression in the following manner:
g(x) = f(k · x), for 0 < k < 1 (1)
If we know that f(x) = x², then the equation of g(x) is:
g(x) = (k · x)², 0 < k < 1
For the definition of <em>horizontal</em> compression, the function f(x) = x² is horizontally compressed to the function g(x) = (k · x)², for 0 < k < 1.
To learn more on rigid transformations: brainly.com/question/1761538
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Answer:
y = -4x + 28
Step-by-step explanation:
yeah-ya........ right?
216. hope this helps you.
Answer:
The vertex for the function f(x) = 3(x – 2)2 + 4 is at (2, 4).
Step-by-step explanation:
Find the vertex for f(x) = 3 (x - 2)^2 + 4
f(x) = 3 (x - 2)^2 + 4 can also be written as:
y = 3 (x - 2)^2 + 4
To find critical points, first compute f'(x):
d/(dx)(3 (x - 2)^2 + 4) = 6 (x - 2):
f'(x) = 6 (x - 2)
Solve 6 (x - 2) = 0
6x - 12 = 0
6x = 12
x = 2
iI you substitute x = 2 in 3 (x - 2)^2 + 4 then you get:
y = 3 (x - 2)^2 + 4
x = 2
y = 3 (2 - 2)^2 + 4
y = 3 (0)^2 + 4
y = 3 (0) + 4
y = 4
Answer: The vertex for the function f(x) = 3(x – 2)2 + 4 is at ( 2, 4 ).
