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3 years ago

What are the coordinates of the treasure? If necessary, round the coordinates to the nearest tenth.

Mathematics

2 answers:

kicyunya [14]3 years ago

8 0

If treasure is midway of two points then treasures point is(x1+x2/2,y1+y2/2)

16+3/2, 21+2/2

Else any point shown byyour options is treasure's point

Drupady [299]3 years ago

6 0

Answer:

ITS D LAST CHOICE!!

Step-by-step explanation:

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Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

4 years ago

6. Find the product:<br> (x² + 8x - 3)(x + 1)

olga_2 [115]

Answer:

x^3+9x^2-3x^2-3

Step-by-step explanation:

You can use a various of methods but when you use the box method you multiply each separately.

Like you would multiply x² by x, 8x by x, -3 by x (thats the first row)

x² by 1, 8x by 1, -3 by 1 ( for the second row)

Then you get those final variables and combine like terms getting the answer above

8 0

3 years ago

How would I calculate/measure angles without a protracter?

atroni [7]

Answer:

you would calculate angles with a protractor by using degrees.

Step-by-step explanation:

the center would be put at one corner and then u measure the side you want to know the angle of. hope this helped.

4 0

4 years ago

Read 2 more answers

Measure

yaroslaw [1]

Answer:Measure

Angle

48°

(6. - 28)

(2x)

Find the value of x. Then find the measures of angles B and C

Enter your answers in the boxes.

mZB=

mZC =

Step-by-step explanation:

7 0

3 years ago

Hi!! So I am doing test corrections for a test that I did bad on but I need to know what is the equation for this??

Sedaia [141]

Answer:

u can use fraction calculator

Step-by-step explanation:

just go and search 'fraction calculator'

8 0

3 years ago