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nikklg [1K]
3 years ago
7

Distances in space are measured in light-years. The distance from Earth to a star is 4.1 × 1013 kilometers. What is the distance

, in light-years, from Earth to the star (1 light-year = 9.46 × 1012 kilometers)?
0.23 light-year
2.36 light-years
4.33 light-years
5.36 light-years
Mathematics
2 answers:
Vinvika [58]3 years ago
8 0
How many 'light years distance' can fit in the distance from earth to the star

So we have to divide:

4.1 x 10^13 / 9.46 x 10^12 = 4.33

USPshnik [31]3 years ago
3 0

Answer:

The distance, in light-years, from Earth to the star is 4.33 light- years.

Step-by-step explanation:

As given

Distances in space are measured in light-years.

The\ distance\ from\ Earth\ to\ a\ star\ is\ 4.1\times 10^{13}\kilometers.

1 light-year = 9.46\times 10^{12}\ kilometers

As

1\ kilometer = \frac{1}{9.46\times 10^{12}} \ light\ years

Thus

4.1\times 10^{13}\ kilometer = \frac{4.1\times 10^{13}}{9.46\times 10^{12}} \ light\ years

by using the exponent property .

\frac{x^{a}}{x^{b}} = x^{a-b}

4.1\times 10^{13}\ kilometer =0.433\times 10^{13-12} \ light\ years

4.1\times 10^{13}\ kilometer =0.433\times 10^{1} \ light\ years

4.1\times 10^{13}\ kilometer =\frac{433}{1000} \times 10^{1} \ light\ years

4.1\times 10^{13}\ kilometer =\frac{433}{100}\ light\ years

4.1\times 10^{13}\ kilometer = 4.33\ light\ years

Therefore the distance, in light-years, from Earth to the star is 4.33 light- years.


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John makes $14 an hour, h, plus $20 in tips at the end of the night. How much will John make if he works 9 hours?
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The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 3.6 cars and a
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Answer:

X \sim N(3.6,5)  

Where \mu=3.6 and \sigma=5

Then we have:

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With the following parameters:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

Let X the random variable that represent the number of cars running a red light of a population, and for this case we know the distribution for X is given by:

X \sim N(3.6,5)  

Where \mu=3.6 and \sigma=5

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

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SashulF [63]

Answer:

The equations are:

4H + 3P = 13.75

2H + 5P = 11.25

Hotdog = 2.50

Pretzel = 1.25

Step-by-step explanation:

Let:

H = hot\ dog

P =Pretzel

For Tina:

4H + 3P = 13.75

For Doug:

2H + 5P = 11.25

Solving for the price of both items:

We have:

4H + 3P = 13.75 --- (1)

2H + 5P = 11.25 --- (2)

Multiply (2) by 2

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-------------------

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Subtract (3) from (1)

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----------------------

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