A single card is drawn from a standard 52 card deck.

Susan is buying three different colors of tiles for her kitchen floor. She is buying 25 more red tiles than beige tiles, and thr

Vanyuwa [196]

Let us assume that the number of beige tiles bought by Susan = B
Number of red tiles bought by Susan = R
Number of navy-blue tiles bought by Susan =N
Number of tiles bought altogether = 435
Now from the given question we know:
Number of red tiles bought is 25 more than the number of beige tiles.
So
R = 25 + B
Number of navy blue tiles bought is 3 times that of the number of beige tile bought
So
N = 3B
We already know that the total number of tiles bought is 435
Hence
B + R + N = 435
B + (25 + B) + 3B = 435
5B + 25 = 435
5B = 435 -25
5B = 410
B = 82
R = 25 + B
   = 25 + 82
   = 107
N = 3B
   = 3 * 82
   = 246
So the number of Beige tiles bought by Susan = 82
The number of red tiles bought by Susan = 107
The number of navy-blue tiles bought by Susan = 246

5 0

3 years ago

What is the ratio of 2 soccer balls to 6 footballs

LiRa [457]

2 to 6 is the answer

5 0

3 years ago

Read 2 more answers

Prince Ivan rides gray wolf and a constant speed from kings castle to the magic apple garden in five hours. on the return trip t

borishaifa [10]

Answer:

The original speed of the grey wolf can be 9 and/or 48 km/hour

Step-by-step explanation:

There are two trips. One to King Castle (KC) to Magic Apple Garden (MAG), and then back (MAG - KC).

First trip: KC - MAG

It takes the same distance as MAG - KC so distance can be D for both.

Then it is stated that it takes 5 hours or 300mins for him to go from KC - MAG, and the speed is constant.

Let x be speed.

So the equation for this is:

D=5x

Second trip: MAG - KC

Here he goes 36 mi at constant speed (x), then picks up his speed by 3 km/hour (x+3).

For Time:

He reaches to KC, 15 mins earlier than KC - MAG, so he reaches there in 4.75 hours or in 275 min.

The problem splits into two as there are two different times, for the two parts of the journey or distance for MAG - KC.

Let T#1 = a, and T#2 = b.

Let D#2 = D-36

The equation for a:

a = 36/x --> This is he is at a constant speed and went for 36mi.

b = (x+3)/D#2

These two equation have to be added as (a+b) = 4.75 --> 4.75 is the total time for MAG - KC.

So the equation is:

36/x + (5x-36)/x+3 = 4.75 --> Knowing (a+b) = 4.75, just put 4.75 as the equal, and add the fractions that equal (a) and (b).

Now Solve:

36/x + (5x-36)/x+3 = 4.75

0.25s^2 + 108 + 5s^2 - 36s = 4.75s*(s+3)

0.25s^2 - 14.25s + 108 = 0

(14.25 +- Square root (203.06 - 108))/0.5

(14.25 +- Square root (95.0625))/0.5

(14.25 +- 9.75)/0.5

Answer:

s = 9, s=48.

Therefore the original speed of the grey wolf can be 9 and/or 48 km/hour.

8 0

2 years ago

Solve for x. PLZ WAIT FOR THE PHTO TO UPLOAD

stepan [7]

6x² - 5x + -21 = 0

Because this whole equation equals zero, we must simply factorize the first half of the equation, or the left side.

(3x - 7)(2x + 3) = 0

I was never really taught a specific way to factorize, so I usually just guess and check when factorizing. It usually takes a long time, it always gives you the tight answer.

Then, take each equation and make it equal zero.

3x - 7 = 0 AND 2x + 3 = 0

3x - 7 = 0

Add 7 to both sides.

3x = 7

Divide both sides by 3.

x = 7/3

Now, we do our second equation.

2x + 3 = 0

Subtract 3 from both sides.

2x = -3

Divide both sides by 2.

x = -3/2

So, x = 7/3 AND x = -3/2

So, your answer is C) x = 7/3, x = -3/2

~Hope I helped!~

7 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

2 years ago