Consider the solubility graph above. According to the prompt, at 105oC, which of the solutes would still be unsaturated?

An unsuspecting bird is coasting along in an easterly direction at 1.00 mph1.00 mph when a strong wind from the south imparts a

grin007 [14]

Answer:

2.375 m, 54°

Explanation:

I will be doing this applying the vector format of i and j. I hope that's not confusing for you. Where, i = East and j = North.

First, we convert the velocity from miles per hour to meters per second. Remember that 1 mile = 1609 meters

u = 1 mph East = 1.00i + 0j mph

u = (1.00i + 0j) mph * (1609 m / 1 mile) * ( 1 hr / 3600 s) = 0.45i + 0j m/s

a = 0.4 m/s² FROM THE SOUTH

a = 0.4 m/s² North = 0i + 0.4j m/s²

Next, we proceed to use the equation of motion to solve

sf = si + ut + 1/2at²

Let's assume that si = 0, this means that

sf = ut + 1/2at², now we substitute for u, t and a to get

sf = (0.45i + 0j m/s) * 3.1 s + 1/2 * (0i + 0.4j m/s²) * (3.1s)²

sf = (1.395i + 0j m) + (0+1.922j m)

sf = 1.395i + 1.922j m

This means that after 3.1 s, the birds displacement from the start is 1.395 m in the East direction and 1.922 m in the North direction.

Finding the resultant now will be

|sf| = √(1.395² + 1.922²) m

|sf| = √(1.946 + 3.694) m

|sf| = √5.64

|sf| = 2.375 m

direction = Tanθ = (j/i)

θ = Tan^-1 (j/i)

θ = Tan^-1(1.922/1.395)

θ = Tan^-1(1.378)

θ = 54° North East

4 0

4 years ago

what does a velocity vs time graph look like for constant velocity if the speed is 2m/s. And the time is not given.

Ulleksa [173]

Distance-time graph is the plot of distance travelled by a body against time. So it will tell us about the journey made by a body and its speed. Below is an example of a distance-time graph, if it is a straight horizontal line than the body is stationary, its speed is zero, if the line is diagonal than its moving with a constant speed and if it is anything other than a straight line then the speed is varying.

4 0

3 years ago

A railroad car moves under a grain elevator at a constant speed of 3.20 m/s. Grain drops into the car at the rate of 240 kg/min.

dedylja [7]

Answer:

F = 768 N

Explanation:

It is given that,

Speed of the elevator, v = 3.2 m/s

Grain drops into the car at the rate of 240 kg/min, $\dfrac{dm}{dt}=240\ kg/min = 4\ kg/s$

We need to find the magnitude of force needed to keep the car moving constant speed. The relation between the momentum and the force is given by :

$F=\dfrac{dp}{dt}$

$F=m\dfrac{dv}{dt}+v\dfrac{dm}{dt}$

Since, the speed is constant,

$F=m\dfrac{dv}{dt}$

$F=v\dfrac{dm}{dt}$

$F=3.2\times 240$

F = 768 N

So, the magnitude of force need to keep the car is 768 N. Hence, this is the required solution.

5 0

4 years ago

What challenges are faced by scientist investigating effects of radiation in Chernobyl and Eniwetok Atoll in the Chernobyl accid

Andrew [12]

Answer:

The health hazard of directly going to these places to take direct readings and observations.

Explanation:

The Chernobyl accident was a catastrophic radioactive accidents, with an immediate fatal effect on some victims (mostly firemen and law enforcement officers). Scientists investigating the effects of the radiation left on the venues of the accident face a health risk if they intend to carry out a full scale on-field testing and experiment. Some of the relocated occupants of these places, that have long been relocated, have shown some health effect of the radiation. And scientist studying and working on these places for too long stand a risk of developing health complications if they are exposed to the radiations for too long.

8 0

4 years ago

What is the period of a water wave with a frequency of 0.5 Hz?

timama [110]

The period of a water wave with a frequency of 0.5 Hz is 2 seconds. Frequency is the inverse of the period (t) and it is the number of oscillations per unit time or is the number of repetitions of an event by an object per unit time. Frequency can also be calculated in terms of wavelength and speed of light.

5 0

2 years ago