Calculate the magnitude of the particle accelerator's magnetic field that causes an ionized helium atom (+2q e) with a momentum
1 answer:
Answer:
The magnetic field of the particle is 1.5 T.
(C) is correct option.
Explanation:
Given that,
Momentum of particle
Radius = 1.0 km
Charge of the particle
We need to calculate the magnetic field
Using relation of radius of path in magnetic field
Here mv = p
Put the value into the formula
Hence, The magnetic field of the particle is 1.5 T.
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Answer:
(a) 348.4 m
(b) 256.7 m/s
(c) 127.2 m/s^2
Explanation:
(a) at t = 4 s
x = 2.3 x 4 + 5.3 x 4 x 4 x 4
x = 348.4 m
(b) The derivative of displacement function gives the value of instantaneous velocity.
So, v = dx / dt = 2.3 + 5.3 x 3 x t^2
v = 2.3 + 15.9 t^2
Put t = 4 s
So, v = 2.3 + 15.9 x 4 x 4
v = 256.7 m/s
(c) The derivative of velocity function with respect to time gives the value of instantaneous acceleration.
So, a = dv / dt = 5.3 x 3 x 2 x t
a = 31.8 t
Put t = 4 s
a = 31.8 x 4 = 127.2 m/s^2
Answer:
○ 0
Explanation:
Even if the athelete runs four laps of a 400 m track, its displacement will be 0 because the displacement is the shortest distance from its to final position. And, here the final and initial position is same since he comes to its initial position after covering certain distance. So, displacement is 0.