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mr Goodwill [35]
3 years ago
10

mila has completed 4 birdhouses. thats is 40% of the bitdhouses she wants to build.how many birdhouses does she want to build

Mathematics
1 answer:
aivan3 [116]3 years ago
7 0

Answer:

10 birdhouses

Step-by-step explanation:

floor gang aooh sub to pewdiepie

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Apple orchard sells Apple's in bags of 10. The orchard sold a total of 2,430 apples one day. How many bags of Apple's was this
zlopas [31]

divide them:

2430/10 = 243 bags

5 0
3 years ago
Geometry need help answering
Dmitry_Shevchenko [17]
Answer:

GI is supplementary, Given
KH =JH , given
Midpoint

Couldnt see how many boxes u needed but this should help good luck
8 0
3 years ago
James is playing his favorite game at the arcade. After playing the game 333 times, he has 888 tokens remaining. He initially ha
lesantik [10]

Answer:

t(g)= -4g + 20

Step-by-step explanation:

James is playing his favorite game at the arcade. After playing the game 3 times, he has 8 tokens remaining. He initially had 20 tokens, and the game costs the same number of tokens each time. The number tt of tokens James has is a function of gg, the number of games he plays

Solution

Let

g=No. of games James plays

t= No. of tokens James has.

Find the slope using

y=mx + b

Where,

m = Slope of line,

b = y-intercept.

Before James started playing the games, he has a total of 20 tokens.

That is, when g=0, t=20

After James played the games 3 times, he has 8 tokens left

That is, when g=3, t=8

(x,y)

(0,20) (3,8)

m=y2-y1 / x2-x1

=(8-20) / (3-0)

= -12 / 3

m= -4

Slope of the line, m= -4

y=mx + b

No. of tokens left depend on No. of games James plays

t is a function of g.

t(g)

t(g)= -4g + 20

3 0
3 years ago
Krisa divides a number by 10. Then she divides the same number by 50. Which quotient is greater? How can you tell?
weeeeeb [17]

Step-by-step explanation:

the quotient of 10 is bigger than the quotient of 50

6 0
3 years ago
Tank is a car salesman at EH Auto Dealer. The data below
Licemer1 [7]

Answer:

\begin{array}{cc}{Cars} & {Months} & {28} & {3} & {29} & {3} & {30} & {1} & {31} & {2} \ \end{array}

Step-by-step explanation:

Given

<u>Data:</u>

29\ 30\ 29

29\ 31\ 28

28\ 31\ 28

Required

Construct a frequency table

From the given data, we have:

<em>28 occurs 3 times</em>

<em>29 occurs 3 times</em>

<em>30 occurs 1 time</em>

<em>31 occur 2 times</em>

Hence, the frequency table is:

\begin{array}{cc}{Cars} & {Months} & {28} & {3} & {29} & {3} & {30} & {1} & {31} & {2} \ \end{array}

6 0
3 years ago
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