Ask question

Ask question

All categories

3 years ago

13

I didn’t mean to post this and I can’t delete it so how are you and how’s your day and if you know how to delete things please t

ell me

1 answer:

olchik [2.2K]3 years ago

5 0

I don’t feel like doing school and I keep getting distracted by this app

You might be interested in

Find the surface area of the triangular prism please.

Kobotan [32]

Surface area = area of 3 rectangles + 2 triangles

= 3*(3*7) + 2 * ( 1/2 * 3 * 2.6)

= 63 + 2* 3.9

= 70.8 in^2

3 0

3 years ago

if a committee of 4 is to be chosen at random from the class of 11 students what is the probability of any particular commuter b

Darina [25.2K]

i think the answer is 4/11 because the 4 people has a 1% chance out of the 11 people

7 0

3 years ago

What is the solution to the trigonometric inequality 2sin(x)+3>sin ^2(x) over the interval

navik [9.2K]

The intervals that satisfy the given trigonometric Inequality are; 0 ≤ x < 3π/2 and 3π/2 < x ≤ 2π

<h3>How to solve trigonometric inequality?</h3>

We are given the trigonometric Inequality;

2 sin(x) + 3 > sin²(x)

Rearranging gives us;

sin²(x) - 2 sin(x) - 3 < 0

Factorizing this gives us;

(sin(x) - 3)(sin(x) + 1) < 0

Thus;

sin(x) - 3 = 0 or sin(x) + 1 = 0

sin(x) = 3 or sin(x) = -1

sin(x) = 3 is not possible because sin(x) ≤ 1.

Thus, we will work with;

sin(x) = -1 for the interval 0 ≤ x ≤ 2π radians.

Then, x = sin⁻¹(-1)

x = 3π/2.

Now, if we split up the solution domain into two intervals, we have;

from 0 ≤ x < 3π/2, at x = 0. Then;

sin²(0) - 2 sin(0) - 3

= 0² - 0 - 3

= -3 < 0

Thus, the interval 0 ≤ x < 3π/2 is true.

From 3π/2 < x ≤ 2π, take x = 2π. Then;

sin²(2π) - 2 sin(2π) - 3

= 0² - 0 - 3

= -3 < 0

Thus, the interval 3π/2 < x ≤ 2π is also true.

Read more about trigonometric inequality at; brainly.com/question/27862380

#SPJ1

3 0

1 year ago

The angle of elevation of the top of the tower from a point on the ground is 30 degree, If the height of the tower is 40 space m

kiruha [24]

Answer:

$40\sqrt3\ m$

Step-by-step explanation:

Given that,

The height of the tower, h = 40 m

The angle of elevation is 30°

We need to find the distance between the tower and the point. Let the distance is x. Using trigonometry,

$\tan(30)=\dfrac{h}{x}\\\\\dfrac{1}{\sqrt3}=\dfrac{40}{x}\\\\x=40\sqrt3\ m$

So, the distance between the tower and the point is equal to $40\sqrt3\ m$ .

7 0

3 years ago

Least to greatest 2.3 2 4/5 2.6

Volgvan

2.3 is smaller than 2.6: we can see it just by looking at the digits from left to right.

now, where does 2 $\frac{4}{5}$ stand?

its fraction part is equal to

$\frac{4*2}{5*2}= \frac{8}{10}$

do that means that 2 $\frac{4}{5}$ =2.8

which is bigger than 2.6

so the final order is

2.3 2.6 2 $\frac{4}{5}$

5 0

3 years ago