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Nana76 [90]
3 years ago
9

Solve x2 − 12x + 5 = 0 using the completing-the-square method. x = six plus or minus the square root of five x = negative six pl

us or minus the square root of five x = six plus or minus the square root of thirty one x = negative six plus or minus the square root of thirty one
Mathematics
1 answer:
Andru [333]3 years ago
5 0

we are given

x^2-12x+5=0

we have to solve it by completing square method

step-1: Move 5 on right side

x^2-12x+5-5=0-5

x^2-12x=-5

step-2: Break middle term

x^2-2*6*x=-5

step-3: Add 6^2 both sides

x^2-2*6*x+(6)^2=-5+(6)^2

(x-6)^2=31

step-3: Solve for x

\sqrt{(x-6)^2} =\sqrt{31}

we wil get two values

First value is

x-6=\sqrt{31}

add both sides 6

x-6+6=6+\sqrt{31}

x=6+\sqrt{31}

Second value is

x-6=-\sqrt{31}

add both sides 6

x-6+6=6-\sqrt{31}

x=6-\sqrt{31}

so, solutions are

x=6+\sqrt{31}

x=6-\sqrt{31}.............Answer

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Explanation:

Let's put the information in a table step-by step.

                                                (number of remaining students)

                                                        Juniors          Seniors

Condition

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  • 15 seniors left                                                   S - 15
  • Twice juniors as seniors         2(S - 15)
  • 3/4 of the juniors left              1/4×2(S - 15)
  • 1/3 of seniors left                                             2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

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Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

2/3\times (S - 15) -  1/4\times 2(S - 15) = 8

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  • Distribution property:

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  • Addtion property of equalities:

8S-6S=96+120+90

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2S=306

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That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

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Just substitute S with 153 fo find the number of students that remained to perfom in the musical:

          2/3\times (153-15)+1/4\times 2(153-15)\\ \\ 2/3(138)+1/2(138)

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