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solniwko [45]
3 years ago
12

Which function has zeros at x = 10 and x = 2? f(x) = x2 – 12x + 20 f(x) = x2 – 20x + 12 f(x) = 5x2 + 40x + 60 f(x) = 5x2 + 60x +

100
Mathematics
2 answers:
valentina_108 [34]3 years ago
7 0

Answer:

The answer on Edgenuty is A.

Step-by-step explanation:

4vir4ik [10]3 years ago
5 0
To find the correct function, just plug in 10 and 2 to see if the function equals zero with both numbers.

f(x)=x^2-12x+20
f(10)=100-120+20
f(10)=0         --> that's what we want, so let's check the other number

f(x)=x^2-12x+20
f(2)=4-24+20
f(2)=0          --> perfect. this function has zeros at both x=10 and x=2

The function that has zeros at both x=10 and x=2 is f(x)=x^2-12x+20.
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A group of 72 children completed a survey on what kind of sport they like. The choices were: Chess, Swimming, and Football. Ever
Svetach [21]

Answer:

19/72

Step-by-step explanation:

To calculate the probability that a randomly-chosen child from this group likes either Chess or Swimming but not Football?

We already know the number that liked chess only which is 10, we have to solve for those that liked swimming only which is

8+7+16+x = 40

x which represent swimming only is

40-31 = 9

Thus probability = 10/72 + 9/72 = 19/72

3 0
3 years ago
How can victoria justify step 3 of her work
Wittaler [7]
A little more info please?
4 0
3 years ago
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*20 POINTS*
Paraphin [41]

Answer:

If you want to use the Rational Zeros Theorem, as instructed, you need to use synthetic division to find zeros until you get a quadratic remainder.

P: ±1, ±2, ±3, ±6  (all prime factors of constant term)

Q: ±1, ±7              (all prime factors of the leading coefficient)

P/Q: ±1, ±2, ±3, ±6, ±1/7, ±2/7, ±3/7, ±6/7  (all possible values of P/Q)

Now, start testing your values of P/Q in your polynomial:

f(x)=7x4-9x3-41x2+13x+6

You can tell f(1) and f(-1) are not zeros since they're not = 0Now try f(2) and f(-2):

f(2)=7(16)-9(8)-41(4)+13(2)+6

       112-72-164+26+6 ≠ 0

f(-2)=7(16)-9(-8)-41(4)+13(-2)+6

       112+72-164-26+6 = 0  OK!! There is a zero at x=-2

This means (x+2) is a factor of the polynomial.

Now, do synthetic division to find the polynomial that results from

(7x4-9x3-41x2+13x+6)÷(x+2):

-2⊥ 7   -9   -41    13     6

         -14   46   -10    -6          

      7  -23   5       3     0     The remainder is 0, as expected

The quotient is a polynomial of degree 3:

7x3-23x2+5x+3

Now, continue testing the P/Q values with this new polynomial.  Try f(3):

f(3)=7(27)-23(9)+5(3)+3

      189-207+15+3 = 0  OK!!  we found another zero at x=3

Now, another synthetic division:

3⊥ 7   -23    5     3

          21   -6   -3_

    7    -2    -1    0  

The quotient is a quadratic polynomial:

7x2-2x-1  This is not factorable, you need to apply the quadratic formula to find the 3rd and 4th zeros:

x= (1±2√2)÷7

The polynomial has 4 zeros at x=-2, 3, (1±2√2)÷7

Step-by-step explanation:

7 0
3 years ago
Suppose at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard. Also, 30% of the
Doss [256]

Answer:

0.6,0.7,0.3 neither disjoint nor independent.

Step-by-step explanation:

Given that at a large university, 60% of the students have a Visa card and 40% of the students have a MasterCard.

A= visa card

B = Master card

P(A) = 0.60 and P(B) = 0.40

P(AUB)' = 0.30

i.e. P(AUB) = 0.70

Or P(A)+P(B)-P(AB) =0.70

P(AB)= 0.30

Randomly select a student from the university.

1) the probability that this student does not have a MasterCard.

= P(B') = 1-0.4 =0.6

2.  the probability that this student has either a Visa card or a MasterCard.

=P(AUB) = 0.70

3. Calculate the probability that this student has neither a Visa card nor a MasterCard.

=P(AUB)' = 0.30

4. Are the events A and B disjoint? Are the events A and B independent?

A and B have common prob 0.30 hence not disjoint.

P(AB) ≠P(A)P(B)

Hence not independent

6 0
3 years ago
$10,000 is compounded quarterly at 12% interest for t years. what expression represents the amount of money after t years.
fredd [130]

we know that  

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=t\ years\\ P=\$10,000\\ r=0.12\\n=4  

substitute in the formula above  

A=10,000(1+\frac{0.12}{4})^{4t}  

A=10,000(1+0.03)^{4t}  

A=10,000(1.03)^{4t}  

therefore

<u>the answer is</u>

A=10,000(1.03)^{4t}  

4 0
3 years ago
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