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Inessa [10]
3 years ago
14

Grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height. how high

is the pile (to the nearest hundredth of a foot) when it contains 1110 ft3 of grain?
Mathematics
1 answer:
bezimeni [28]3 years ago
7 0

Given that grain is falling from a chute onto the ground, forming a conical pile whose diameter is always three times its height.

So if D is the diameter and h is the height of the conical pile then we can write:


D=3h

We know that diameter = 2r, where r is the radius

2r=3h

r=\frac{3h}{2}

Volume of conical pile is given by formula

V=\frac{1}{3}\pi r^2h

Given that volume is 1110 cubic feet.

Now plug the values of Volume and r into equation of volume

1110=\frac{1}{3}\pi (\frac{3h}{2})^2h

1110=\frac{1}{3}\pi\cdot\frac{9h^2}{4}\cdot h

1110=\pi\cdot\frac{3h^3}{4}

1110\cdot\frac{4}{3\pi}=h^3

471.098631552=h^3

take cube root of both sides

7.78103342467=h

Hence height is approx 7.78 feet.

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