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3 years ago

Duffy repairs shoes. He decided to raise all

Mathematics

2 answers:

LekaFEV [45]3 years ago

8 0

Answer:

17.53

Step-by-step explanation:

2.53+15=17.53

If its not correct see yahhh

makvit [3.9K]3 years ago

3 0

I think it will be 17.53 but I’m not sure

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Which expression represents "8 times the sum of a number and 3"?

yulyashka [42]

Answer:

8(x + 3)

Step-by-step explanation:

5 0

4 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

Please help me solve this

OlgaM077 [116]

Answer:

645320

Step-by-step explanation:

Given: 6_5_2_

If a multiplication sign is placed between the second and third digit, and an equal sign is placed between the third and fourth digit, then

6_ × 5 = _2_

The passcode contains 6 DIFFERENT digits, so we know the missing numbers cannot be 6, 5, or 2.

So, do a trial and error session of multiplying 5 by numbers it could possibly be (60, 61, 63, 64, 67, 68, 69).

64 × 5 = 320. It is the only equation that is both correct and matches the digits given, so the missing digits are 4, 3, and 0. Barry's passcode is 645320.

4 0

4 years ago

Evaluate the function below for x = 2.<br>f (x) = 4x^3 - x^2 - 5x+7<br>

nexus9112 [7]

Answer: $f(2)=25$

Step-by-step explanation:

You know that the given function is:

$f(x)=4x^3-x^2-5x+7$

You know that you must evaluate this function for $x=2$ .

Then, to evaluate the function for $x=2$ , you need to substitute this value into the given function and simplify it.

Therefore, you get:

$f(x)=4x^3-x^2-5x+7\\f(2)=4(2)^3-(2)^2-5(2)+7\\f(2)=4(8)-(4)-10+7\\f(2)=32-4-10+7\\f(2)=25$

So, the answer is: $f(2)=25$

8 0

3 years ago

What is the length of the hypotenuse of a right triangle if each of the two legs is 4 units? Square root of 8 units 4 units Squa

Alex787 [66]

The answer would be √32 or 4√2 (which is simplified) because of pythagoras' theorem. If we substitute a = b = 4 into it, then c must equal the root of 16 + 16, or 32.

7 0

3 years ago

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