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Umnica [9.8K]
3 years ago
13

Write the equation of the line in slope-intercept form that has the following points: (4, 5) (-1, 2)

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

C. y = 3/5x + 13/5

Step-by-step explanation:

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Which of the equations below could be the equation of this parabola?
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Answer:

the answer is "B"

the "a" (as in ax^2) is negative thus the parabola "goes downward"

Step-by-step explanation:

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A u B u C A=(a,b,c,d,e) B=(d,e,f,g,h,i) C=(a,e,i,o,u) help class 8​
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If U = { a, b, c, d, e, f, g, h} , find the complements of the following sets:(i) A = {a, b, c} (ii) B = {d, e, f, g} (iii) C = {a, c, e, g} (iv) D = { f, g, h, a}

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3 years ago
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Free easy points~<br><br> Find the surface area of this triangular prism.
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Surface area is the sum of area of all surfaces.

In the given diagram , we have two identical triangles , with height = 20 cm and base = 25 cm. Area of triangle = (1/2)*base * height.

So for the given triangle , area = 2*(1/2)*20*25 = 500 cm square .

We have a bottom rectangle whose area is 25*40 = 1000 cm square. A sideby rectangle, whose area is 35*40= 1400 cm square and a backwards rectangle, whose area is 20*40 = 800 cm square.

So the surface area = 500+1000+1400+800 =3700 cm square.

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Over the interval [0, 2π), what are the solutions to cos(2x) = cos(x)? Check all that apply.
valentinak56 [21]

Answer:

Step-by-step explanation:

given the expression;

cos(2x) = cos(x)

According to trig identity;

cos(2x) = cos(x+x)

cos(2x) = cos x cos x - sinx sinx

cos(2x) = cos²(x)-sin²(x)

cos(2x) = cos²(x)-(1-cos²x)

cos(2x) = cos²(x)+cos²x-1

cos(2x) = 2cos²(x)-1

2cos²(x)-1 = cos(x)

let P = cosx

2P²-1 = P

2P²-P-1 = 0

Factorize;

2P²-2P+P-1 = 0

2P(P-1)+1(P-1) = 0

2P - 1 = 0 and P-1 = 0

P = 1/2 and 1

cosx = 1/2 and cos x = 1

x = arccos 1/2

x = π/3

Also;

x = arccos1

x = 0

Hence the value of x are 0 and  π/3

Also the angle = π+ π/3 = 4π/3

The angles are 0, π/3 and 4π/3

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The y axis intercepts the linear function at positive 3
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