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irina [24]
2 years ago
9

What is the solution to the equation below? please help!!​

Mathematics
2 answers:
Mariulka [41]2 years ago
5 0

Step-by-step explanation:

here is the answer bae. Feel free to ask for more

Zanzabum2 years ago
3 0

Answer:

Have you tried photo math.? It can help you find the answer

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Which fraction has a terminating decimal?<br> - 11/19<br> - 4/7<br> - 1/3<br> - 3/150
babunello [35]
<h3>Answer: D) 3/150</h3>

==========================================================

Explanation:

With the use of a calculator, we see that,

  • 11/19 = 0.57894736842106...., the decimals eventually repeat; but unfortunately my calculator ran out of room to show the repeating portion
  • 4/7 = 0.5714285714285714..., the block "571428" repeats forever
  • 1/3 = 0.333333.... the 3s go on forever
  • 3/150 = 0.02

So 3/150 converts to the terminating decimal 0.02

The word "terminate" means "stop". In the other decimal values, the decimal digits go on forever repeating the patterns mentioned.

----------------------

A non-calculator approach will have us simplify 3/150 into 1/50 after dividing both parts by the GCF 3. Then notice how 50 has the prime factorization of 2*5*5. The fact that the denominator 50 can be factored in terms of only 2's and 5's is enough evidence to conclude that the fraction converts to a terminating decimal.

If the denominator factors into some other primes, other than 2s and 5s, then we don't have a terminating decimal. So that's why 11/19, 4/7 and 1/3 convert to non-terminating decimals.

6 0
2 years ago
Pls help i beg i will give brainlist and points
leonid [27]

Answer:

7. 1/10 or 10%

9.5/10

11.5/10

13.9/10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Parallelly lines/angle problem
rodikova [14]

Answer:

142 degrees

Step-by-step explanation:

4 0
2 years ago
-7x^2+14x+21=0<br>answer?​
scoray [572]

Answer:

7(−x−1)(x−3)

Step-by-step explanation:

6 0
3 years ago
Let Z={a,c,{a,b}}. What is |Z|?
Lina20 [59]

Z=\{a,c,\{a,b\}\}

\boxed{|Z|=3} (treat \{a,b\} as one element of Z)

The power set of Z is

\boxed{2^Z=\bigg\{\{\},\{a\},\{c\},\big\{\{a,b\}\big\},\{a,c\},\big\{a,\{a,b\}\big\},\big\{c,\{a,b\}\big\},\big\{a,c,\{a,b\}\big\}\bigg\}}

1. \{a,c\}\subseteq Z is true because both a\in Z and c\in Z.

2. a\in Z is true.

3. \{c\}\subseteq Z is true (same reason as part 1).

4. \{c\}\in Z is false because Z does not contain the set \{c\}, rather just the element c itself.

5. b\in Z is false because the element b on its own simply is not in Z. That b\in\{a,b\} does not mean b\in Z, but that b belongs to a subset of Z.

6. \{a,b\}\in Z is true.

6 0
3 years ago
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