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Nataly_w [17]
3 years ago
7

A turntable A is built into a stage for use in a theatrical production. It is observed during a rehearsal that a trunk B starts

to slide on the turntable 10 s after the turntable begins to rotate. Knowing that the trunk undergoes a constant tangential acceleration of 0.25 m/s2, determine the coefficient of static friction between the trunk and the turntable.
Physics
1 answer:
Ugo [173]3 years ago
3 0

Answer:

0.26

Explanation:

The radius of the table is 2.5 m.

Tangential velocity,

v=u+at\\u=0\\t=10s\\a=0.25m/s^2\\v=0+0.25\times 10 = 2.5 m/s

Net force on the trunk in the plane of the table:

F=m\sqrt{a^2+(\frac{v^2}{r})^2}\\F= m\sqrt{0.25^2+(\frac{2.5^2}{2.5})^2}=2.5m

The trunk slides because the frictional force equals the net force acting on the table:

\mu m g = 2.5 m\\\mu =\frac{2.5}{g} = 0.26

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