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olasank [31]
2 years ago
13

A shopper walks westward 5.4 meters and then eastward 7.8 meters

Physics
1 answer:
RoseWind [281]2 years ago
6 0

Answer:

13.2 meters

Explanation:

(5.4) + (7.8)

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A student walks 4 blocks east, 7 blocks west, 1 block east and then 2 blocks west in an hour what is their velocity
Nutka1998 [239]

Answer:

4 blocks west is final displacement. So 4 blocks per hour

3 0
2 years ago
Three diffrent examples of accelerated motion
LekaFEV [45]

Answer:

The three different examples of the accelerated motion are Falling/dropping of ball, Standing in circular rotating space, moving around the circle.

Explanation:

Acceleration is the change in velocity, which is related to the speed and direction in which the object is travelling. Hence, speeding up, slowing down and turning are few types . A simple example would be dropping a ball: as it falls its speed increases, which is a type of acceleration. A more complicated example would be standing in a circular, rotating space station. A point on the station moves in a circle, meaning that as it travels it must be turning (to remain in circular motion) making this another example of acceleration

3 0
2 years ago
Calculate the Earth's linear momentum, in kilogram meters per second.
Irina18 [472]
The sun orbits the eth at 2kilogram per sec
4 0
3 years ago
A 21.7kg child descends a slide 3.5 m high and reaches the bottom with a speed of 2.2m/s. How much thermal energy due to frictio
nadya68 [22]

Answer:

Subtract the kinetic energy at the bottom from the potential energy loss. The remainder becomes frictional heat.

Potential energy loss:

M g H = 21.7*9.81*3.5 = 745.1 J

Kinetic energy at bottom of slide:

= (1/2) M v^2 = 52.5 J

5 0
3 years ago
A child throws a baseball upward with an initial velocity of 20 m/s. The child wants to throw the baseball at least as high as t
Umnica [9.8K]
When the ball starts its motion from the ground, its potential energy is zero, so all its mechanical energy is kinetic energy of the motion:
E= \frac{1}{2}mv^2
where m is the ball's mass and v its initial velocity, 20 m/s.

When the ball reaches its maximum height, h, its velocity is zero, so its mechanical energy is just gravitational potential energy:
E=mgh

for the law of conservation of energy, the initial mechanical energy must be equal to the final mechanical energy, so we have
\frac{1}{2}mv^2 = mgh
From which we find the maximum height of the ball:
h= \frac{v^2}{2g}= \frac{(20 m/s)^2}{2 \cdot 9.81 m/s^2}=20.4 m

Therefore, the answer is yes, the ball will reach the top of the tree.

5 0
3 years ago
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