Answer:
Since there is attraction force between two charges so the other charge must be - 3C
Explanation:
As we know that the force between two charges is given by formula
here we know that
also we know that
r = 8 cm
now we have
so we have
It’s attract
Now give that Gawk Gawk hand twist vacuum seal combo 30000 playa
Answer: 2.80 N/C
Explanation: In order to calculate the electric firld inside the solid cylinder
non conductor we have to use the Gaussian law,
∫E.ds=Q inside/ε0
E*2πrL=ρ Volume of the Gaussian surface/ε0
E*2πrL= a*r^2 π* r^2* L/ε0
E=a*r^3/(2*ε0)
E=6.2 * (0.002)^3/ (2*8.85*10^-12)= 2.80 N/C
Answer:
There is an attractive force between the rod and sphere.
Explanation:
When negatively charged rod is placed close to the metal sphere then due to the electric field of the rod the opposite free charge of metal sphere comes closer to the rod on one surface
While similar charge in the metal sphere move away from the rod due to repulsion of electric field of rod
This temporary charge distribution of the metal sphere is known as induction
And since opposite charge on the metal surface comes closer to the metal sphere so here we can say that the rod will attract the metal sphere
so here correct answer will be
There is an attractive force between the rod and sphere.
Answer:
a) k = 891.82 N/m
b) e = 0.0143 m = 1.43 cm
c) W = 5.02 J
Explanation:
Step 1: Data given
Mass = 2.60 kg
the spring stretches 2.86 cm = 0.0286
Step 2: What is the force constant of the spring?
Force constant, k = force applied / extension produced
k = (2.60kg * 9.81N/kg) / 0.0326 m
k = 891.82 N/m
b) If the 2.60-kg object is removed, how far will the spring stretch if a 1.30-kg block is hung on it
Extension = F/k = (1.30 kg * 9.81) / 891.82 = 0.0143 m = 1.43 cm
Half the mass means half the extension
c) How much work must an external agent do to stretch the same spring 7.50 cm from its unstretched position?
W = average force used * distance
W = 1/2 * k*e * e = 1/2 k*e²
W = 1/2 * 891.82 * (0.075)² = W = 5.02 J
