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olasank [31]
2 years ago
12

PLEASE HELPP and no pictures please i can't see them on a school computer. Ill appreciate a step by step explanation than you! I

M GIVING 40 POINTS

Mathematics
2 answers:
babunello [35]2 years ago
6 0

Answer:

wassup

Step-by-step explanation:

inna [77]2 years ago
6 0

Answer:

a.

The area of the large circle is 225π cm² [exact] or 706.9 cm² [approximate].

b.

area = 50π/6 cm² [exact]

area = 26.2 cm² [approximate]

Step-by-step explanation:

This problem is easier to solve than it looks.

a.

Area of the large circle.

Look at the top left small circle, the middle circle, and the bottom right circle. You can draw a single line segment that is a diameter of the large circle and also contains the diameters of the three small circles. That means that the diameter of the large circle is 3 times the diameter of each small circle.

R and D are the radius and diameter, respectively, of the large circle.

r and d are the radius and diameter, respectively, of the small circles.

D = 3d

D = 6r = 6(5 cm) = 30 cm

R = 15 cm

A = πr²

A = π(15 cm)²

A = 225π cm²

The area of the large circle is 225π cm² [exact] or 706.9 cm² [approximate].

b.

There are 6 congruent spaces between the small circles and the large circle, and there are another, different 6 congruent spaces between the center circle and the 6 circles around it. The region we need is made up of one space of each type.

The combined area of all 12 spaces is the area of the large circle minus the total area of all the small circles. The area we need to calculate is 1/6 of that combined area.

area = (1/6)(area of large circle - total are of all small circles)

area = (1/6)[225π cm² - 7π(5 cm)²]

area = (1/6)[225π - 175π]cm²

area = 50π/6 cm² [exact]

area = 26.2 cm² [approximate]

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\text {CI} = (60.54, \: 81.46)\\\\

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$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

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MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

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