Answer:
1) A = 0.25 m², 2) V = 0.5 m³, 3) m = 1500 kg, 4) W = 14700 N,
5) P = 58800 Pa
Explanation:
1) The area of the base is square
A = L²
A = 0.5²
A = 0.25 m²
2) The block is a parallelepiped
V = A h
V = 0.25 2
V = 0.5 m³
3) Density is defined
rho = m / V
m = rho V
m = 3000 0.5
m = 1500 kg
4) The weight of a body is
W = mg
W = 1500 9.8
W = 14700 N
5) The pressure is
P = F / A
in this case the force is equal to the weight of the body
P = 14700 / 0.25
P = 58800 Pa
Answer:
Explanation:
According to Coulomb's law, the magnitude of the electric force between two equals charges (q) is given by:
Here k is the coulomb constant and d is the distance between the charges. For two electrons we have:
Finding out the acceleration 12/3 = 4m/s^2
thus it is descending so the actual acceleration would be 9.8-4 = 5.8 m/s^2
the weight will be 90*5.8 = 522 N
522/9.8 = 53.2 kg
Suvat
we have s, u, v and we want a
the suvat equation with these values in is: v^2 = u^2 - 2as
so a = (-v^2 + u^2)/-2s
plug numbers in
a = (-85^2 + 0^2)/-2*36 = 7225/72 = 100.3... ms^-2
Explanation:
Weight/gravity - Downwards
Normal force - Upwards
keep in mind that the length of the arrows of both the weight and the normal forces have to be equal since these are vectors and are equal to each other to cancel each other out