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2 years ago

Which statement describes a property of a proton?

Physics

1 answer:

lesantik [10]2 years ago

7 0

Answer:

They have no charge and are present in the nucleus of an atom. They have a negative charge and travel around the nucleus of an atom. They have a positive charge and travel around the nucleus of an atom

Explanation:

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HELP ASP PLEASED AND THANKS NO LINKS PLEASED AND NO FILES

SOVA2 [1]

Answer:

just search up a ven-diagram and then try to draw it or trace it then use it for ur question

Explanation:

6 0

2 years ago

Vector ~A has a magnitude of 29 units and points in the positive y-direction. When vector ~B is added to ~A, the resultant vecto

timurjin [86]

Answer:

The magnitude of vector B is 43 units and it points in the negative y-direction.

Explanation:

Resultant of vectors = vector sum of all the vectors

Vector A = 29j

Vector B = ?

Resultant of vector A and B = R = -14j

R = A + B

-14j = 29j + B

B = -14j - 29j = - 43j

Hence, the magnitude of vector B is 43 units and it points in the negative y-direction.

4 0

2 years ago

If a system absorbs 155.0 kJ of heat from its surroundings and the system does 45.0 kJ of work on its surroundings, what is the

Ede4ka [16]

The change in the internal energy of the system is 110 kJ.

<h3>What is internal energy?</h3>

Internal energy is defined as the energy associated with the random, disorder motions of molecules.

calculate the change in internal energy, we apply the formula below.

Formula:

ΔU = Q-W.................... Equation 1

Where:

ΔU = Change in internal energy
Q = Heat absorbed from the surroundings
W = work done by the system

From the question,

Given:

Q = 115 kJ

W = 45. 0 kJ

Substitute these values into equation 1

ΔU = 155-45

ΔU = 110 kJ

Hence, The change in the internal energy of the system is 110 kJ.

Learn more about change in internal energy here: brainly.com/question/4654659

4 0

2 years ago

It is difficult to walk on a smooth floor why

quester [9]

Answer:

because theres is not enough friction so it will be super slippery

Explanation:

7 0

2 years ago

A positive point charge Q is located at x=a and a negative point charge −Q is at x=−a. A positive charge q can be placed anywher

Scilla [17]

Answer:

$\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x$

Explanation:

The Coulomb's Law gives the force by the charges:

$\vec{F} = K\frac{q_1q_2}{r^2}\^r$

Let us denote the positon of the charge q on the y-axis as 'y'.

The force between 'Q' and'q' is

$F_1 = K\frac{Qq}{x^2 + y^2}\\F_1_x = F_1\cos(\theta)$

where Θ is the angle between $F_1$ and x-axis.

$F_1_x = K\frac{Qq}{x^2 + y^2}(\frac{x}{\sqrt{x^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}$

whereas

$F_2_x = K\frac{-Qq}{a^2 + y^2}(-\frac{a}{\sqrt{a^2 + y^2}}) = \frac{KQqa}{(a^2 + y^2)^{3/2}}$

Finally, the x-component of the net force is

$\vec{F}_x = \frac{2KQqa}{(a^2 + y^2)^{3/2}} \^x$

8 0

3 years ago