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hodyreva [135]
3 years ago
7

Write the slope-intercept form for the equation of a line parallel to y = -9 and passes through the point (12, -5)

Mathematics
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

Let's see what to do buddy...

_________________________________

Step-by-step explanation:

_________________________________

STEP (1) :

The slope of the line <em>y = - 9</em> is 0(zero) because it is a Horizontal line.

So the slope of the line which is parallel to <em>y</em><em> </em><em>=</em><em> </em><em>-</em><em>9</em><em> </em><em> </em> is <em>zero</em><em> </em>.

_________________________________

STEP (2) :

We have this equation to find the slope-intercept form of the linear functions :

y - y(given \: point) = (slope) \times ( \: x -x(g \: p) \: ) \\

_________________________________

STEP (3) :

Now it is time to put the slope and the given point in the equation :

<em>given</em><em> </em><em>point</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>1</em><em>2</em><em> </em><em>,</em><em> </em><em>-</em><em>5</em><em> </em><em>)</em>

<em>slope</em><em> </em><em>=</em><em> </em><em>0</em><em> </em>

y - ( - 5) = 0 \times (x - 12) \\  \\ y + 5 = 0 \\  \\ y =  - 5

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

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Please find the attached diagram for a better understanding of the question.

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Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR :

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