Come I need answers

Plzzzz help and I'll give you brainliest

sdas [7]

Step-by-step explanation:

Left hand side:

4 [sin⁶ θ + cos⁶ θ]

Rearrange:

4 [(sin² θ)³ + (cos² θ)³]

Factor the sum of cubes:

4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]

Pythagorean identity:

4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]

Complete the square:

4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]

4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]

Pythagorean identity:

4 [1 − 3 sin² θ cos² θ]

Rearrange:

4 − 12 sin² θ cos² θ

4 − 3 (2 sin θ cos θ)²

Double angle formula:

4 − 3 (sin (2θ))²

4 − 3 sin² (2θ)

Finally, apply Pythagorean identity and simplify:

4 − 3 (1 − cos² (2θ))

4 − 3 + 3 cos² (2θ)

1 + 3 cos² (2θ)

3 0

3 years ago

Use an algebraic equation to find the measures of the two angles described below. begin by letting x represent the degree measur

Lina20 [59]

Two angles are said to be supplement when their measure add up to 180 degrees.

Assume that the angle we are looking for is a and its supplement is s (I used s instead of x).

a + s = 180
a = 180 - s ......> equation I

We know that <span>the measure of the angle is eight times greater than its supplement.
This means that:
a = 8s ......> equation II

Substitute by equation II in equation I to get s as follows:
180 - s = 8s
180 = 9s
s = 20 degrees

Substitute in equation I to get the measure of the angle as follows:
a = 180 - s = 180 - 20 = 160 degrees

Based on these calculations:
The measure of the angle is 160 degrees
The measure of its supplement is 20 degrees</span>

4 0

4 years ago

WHOEVER SOLVES ALL OF THEM WILL BE MARKED BRAINLIEST

Alenkasestr [34]

Answer:

1. A(1;5), B(10;23), slope of 2

2. A(10;9), B(4;0), slope of 1.5

3. A(-35/4;6), B(9;-35/6), slope of -2/3

4. A(5;18), B(25,22), slope of 0.2

5. A(2/9;1/3), B(2/3,-1/3), slope of -1.5

Step-by-step explanation:

Substitute values with correct variable and slopemis coefficient of x when x and y-int. are on 1 side, y is on other side and has coefficient of 1. Hope it works!

4 0

3 years ago

Which is the interval notation represent the domain?

Kazeer [188]

Answer:

The first choice, $(-\infty, 7) \cup (7, \infty)$ .

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches $7$ , its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for $x = 7$ . The point $7$ should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of $x = 7$ . Here's how to write that in interval notation:

The set of all real numbers can be expressed as the interval $(-\infty, \infty)$ . Note that infinity $\infty$ (or $(- \infty)$ itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
The set of all real numbers less than (not equal to) $7$ is $(-\infty,7 )$ (both ends are excluded.) The set of all real numbers greater than (not equal to) $7$ is $(7, \infty)$ .
The set of all real numbers that is not equal to $7$ is the union of all real numbers less than $7$ and all real numbers greater than $7$ . The union operator $\cup$ connects two intervals.