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Ymorist [56]
2 years ago
8

Complex numbers [ = square root symbol -[-64 How would I find this?

Mathematics
1 answer:
cestrela7 [59]2 years ago
8 0

-\sqrt{-64}=-\sqrt{8^2\cdot (-1)}-8\sqrt{-1}=-8i

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<em>Hey </em><em>mate!</em><em>!</em>

<em>Answer:</em>

<em>n(</em><em>A)</em><em>=</em><em>1</em><em>2</em>

<em>Solution</em><em>,</em>

<em>A=</em><em>{</em><em>3</em><em>,</em><em>6</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>1</em><em>,</em><em>2</em><em>4</em><em>,</em><em>2</em><em>7</em><em>,</em><em>3</em><em>0</em><em>,</em><em>3</em><em>3</em><em>,</em><em>3</em><em>6</em><em>}</em>

<em>Just </em><em>count </em><em>the </em><em>elements</em><em>,</em>

<em>There </em><em>are </em><em>1</em><em>2</em><em> </em><em>elements </em><em>in </em><em>the </em><em>set.</em>

<em>So </em><em>the </em><em>cardinal </em><em>number </em><em>of </em><em>the </em><em>set </em><em>is </em><em>1</em><em>2</em><em>.</em>

<h2><em>Hope </em><em>it </em><em>helps.</em><em>.</em><em>.</em></h2>
8 0
2 years ago
Read 2 more answers
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