Area of sector CAD = 72 / 360 x pi x 6^2 = 7.2pi = 22.6195 in^2
Therefore, area of segment CED = 22.6195 - 17.18 = 5.44 in^2
Combine like terms so add 4b and 15b together and add 7 and 3 together and then the answer would be 19b-10
-3/2
Down 3
Right 2
As an improper fraction it would be -1 1/2
In a Rhombus the diagonals intersect and divides it in two equal halves.
Therefore LP = 28/2
LP = 14cm
Answered by GauthMath if you like please click thanks and comment thanks
