Answer:
Step-by-step explanation:
its c trust i am a man in my moms bacement
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
Z' = (-5,3)
Step-by-step explanation:
Move two to the (<- left) from -3,5 to get -5, 5
move two down to get -5,3
Answer:
Part A:
-Minimum: 10
-Q1: 17.5
-Median: 30
-Q3: 42.5
-Maximum: 50
Step-by-step explanation:
Part B: IQR= 25
This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.
Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.
