Solve algebraically for x 3600+1.02x<2000+1.04x

Mathematics

1 answer:

pickupchik [31]2 years ago

3 0

Answer:

x > 80,000

Step-by-step explanation:

3600+1.02x<2000+1.04x

The first thing we need to do is to isolate the x's and get all of them on one side, let's start off by subtracting 2,000 from both sides of the equation.

1,600+1.02x<1.04x

Now, subtract 1.02x from both sides to get both the x's on one side.

1600<0.02x

Divide by 0.02 to solve for x.

80,000<x

We can flip the sign and swap the places of the number and variable so that x is on the left side.

x > 80,000

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