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lilavasa [31]
3 years ago
7

Solve algebraically for x 3600+1.02x<2000+1.04x

Mathematics
1 answer:
pickupchik [31]3 years ago
3 0

Answer:

x > 80,000

Step-by-step explanation:

3600+1.02x<2000+1.04x

The first thing we need to do is to isolate the x's and get all of them on one side, let's start off by subtracting 2,000 from both sides of the equation.

1,600+1.02x<1.04x

Now, subtract 1.02x from both sides to get both the x's on one side.

1600<0.02x

Divide by 0.02 to solve for x.

80,000<x

We can flip the sign and swap the places of the number and variable so that x is on the left side.

x > 80,000

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PLEASE HELP IF YOU KNOW AP STATS OR HAVE TAKEN THIS QUIZ!! THANK U
eimsori [14]

Answer:

For A is Y=7x+64 Thats all i know

Step-by-step explanation:

7 0
3 years ago
g natasha is in a class of 30 students that selects 4 leaders. How many ways are there to select the 4 leaders so that natasha i
Papessa [141]

Answer:

<h2>3,654 different ways.</h2>

Step-by-step explanation:

If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).

Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.

nCr = n!/(n-r)!r!

Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.

29C3 = 29!/(29-3)!3!

29C3 = 29!/(26!)!3!

29C3 = 29*28*27*26!/26!3*2

29C3 = 29*28*27/6

29C3 = 3,654 different ways.

This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders

5 0
3 years ago
A tram moved upward 9 meters per second for 36 seconds. What was the total change in the tram's elevation?
anyanavicka [17]

Answer:

324 meters.

Step-by-step explanation:

9*36 :)

8 0
3 years ago
Consider the problem $minimize$ $f(x)=x^4-1$. solve this problem using newton's method. start from $x_0=4$ and perform three ite
stellarik [79]
F(x)=x⁴-1
f'(x)=4x³
Newton’s Method: x[n+1]=x[n]-f(x[n])/f'(x[n]); x[n+1]=x[n]-(x[n]⁴-1)/4x[n]³
x₁=3.00390625
x₂=2.26215...
x₃=1.7182...

X'=X-(X⁴-1)/4X³=X-X/4+1/4X³ is a symbolic way of writing the recursive formula, where X' represents the next iteration.
When X'≈X, -X/4+1/4X³≈0; so X/4≈1/4X³; X≈1/X³, so X⁴≈1 and X⁴-1≈0. But this is f(x)≈0. Hence Newton’s Method converges to a solution.
The rate of change is x[n+1]-x[n]=-(x[n]⁴-1)/4x[n]³=x[n]/4-1/4x[n]³ or symbolically -X/4+1/4X³.
Note that the method converges to one solution. A different x₀ will possibly converge to the solution x=-1.
5 0
3 years ago
Which expression can be simplified as<br> 718?<br> ?<br> • (m2)<br> (nojo<br> o<br> o (no)<br> 6
BabaBlast [244]
The answer is (n^-3)^6
The fourth option
3 0
3 years ago
Read 2 more answers
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