You do 9-3/6-5 and that is 3/1 so the slope is 3 (y2-y1/x2-x1)
The answer is 12/5
Remember: Soh;opposite over Hypotenuse Cah; Adjacent over Hypotenuse Toa; Opposite over Adjacent. SOH CAH TOA
Hope this helps! :)
Answer:
106
Step-by-step explanation:
the angles must make a total of 540°
if you add up all angles it will be 434°
subtract it from the total(540 - 434) and you will find the value of X
Is there a picture? I don't know how to answer without the actual problem. Sorry,
This sine function has the form y = f(x) = a sin (bx + c), where |a| is the amplitude, b is the frequency, and c determines the phase shift.
The period of this sine curve is 2 pi/b, or (in this problem) 2 pi/(1/2).
The phase shift of this curve is -c/b, or -(pi/4)/(1/2). Simplify this.
The amplitude is |-3|, or just 3.
Draw a set of coordinate axes. Draw light horizontal lines through y=3 and y=-3. These are the max and min. values of this sine function.
Plot the phase shift on your x-axis.
Your sine function will begin at (phase shift value, 0) and continue for one period. Add the period to the phase shift value. Draw a sine curve beginning and ending at these two x-values.
I encourage you to share your calculations and to sketch the graph described here. Then I could give you more specific feedback on your work. Good luck!
