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Brrunno [24]
3 years ago
7

What is the value of x in the equation 3x-4y=65 when y=4

Mathematics
2 answers:
vredina [299]3 years ago
3 0
I believe x is equal to 23
Illusion [34]3 years ago
3 0
I think its 23 for this equation
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Who knows this? I’ll mark BRAINLIEST!
mestny [16]

Answer:

i think it's a

Step-by-step explanation:

5 0
3 years ago
Violet's Botanical Garden produced flowers throughout the year. A graph demonstrating how many flowers she produced over a 12-mo
Lady bird [3.3K]

Answer:

  The domain represents a 12-month period of flower production

Step-by-step explanation:

The <em>domain</em> is <em>the horizontal extent of the graph</em>. Both the problem statement and the graph itself tell you that is a 12 month time period.

7 0
3 years ago
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Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel
Airida [17]

Answer:

89.1° or -1.4°  

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

(3) \, t =\dfrac{2}{\cos \theta}

Substitute (3) into (2)

-50 = 600t \sin \theta - 4.9t^{2} =  600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )

Set up a quadratic equation

\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0
3 years ago
I don't understand this I have spent many points on this same question so this time I will be giving brainliest for the first co
Marrrta [24]

Given:

|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|

Solution:

Complex formula:

|a+b i|=\sqrt{(a+b i)(a-b i)}=\sqrt{a^{2}+b^{2}}

Let us simplify one by one.

|3+4 i|=\sqrt{3^{2}+4^{2}}

           =\sqrt{25}

|3 + 4i| = 5

|3-4 i|=\sqrt{3^{2}+(-4)^{2}}

           =\sqrt{25}

|3 - 4i| = 5

|-3+4 i|=\sqrt{(-3)^{2}+4^{2}}

           =\sqrt{25}

|-3 + 4i| = 5

|-3-4 i|=\sqrt{(-3)^{2}+(-4)^{2}}

           =\sqrt{25}

|-3 - 4i| = 5

Substitute these in the given expression:

|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|=5+5+5+5

                                                                  =20

The solution of the expression is 20.

8 0
3 years ago
What is 2.85 as a mixed number
sveticcg [70]
2 85/100
The numbers with the slash in the middle is a fraction.
4 0
3 years ago
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