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Vladimir79 [104]
3 years ago
6

{}^{2} = x {}^{2} + 4" alt="4x {}^{2} = x {}^{2} + 4" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
mario62 [17]3 years ago
8 0

Answer:

x = 1.155

x = -1.155

Step-by-step explanation:

4x² = x² + 4

<h3><u>i</u><u>)</u><u> </u><u>move</u><u> </u><u>variable</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>left-</u><u>hand</u><u> side</u><u> </u><u>and</u><u> </u><u>change</u><u> its</u><u> sign</u></h3>

4x² - x² = 4

<h3><u>ii</u><u>)</u><u> </u><u>colle</u><u>ct</u><u> like</u><u> terms</u></h3>

3x² = 4

<h3><u>iii</u><u>)</u><u> </u><u>divi</u><u>de</u><u> both</u><u> sides</u><u> of</u><u> the</u><u> equation</u><u> </u><u>by</u><u> </u><u>3</u></h3>

<u>\frac{ {3x}^{2} }{3}  =  \frac{4}{3}</u>

{x}^{2}  =  \frac{4}{3}

<h3><u>iv</u><u>)</u><u> </u><u>take the square root to the opposite side of the equation and remember to use </u></h3><h3><u>positive</u><u> and negative </u><u>roots</u></h3>

<u>x =  +  -  \sqrt{ \frac{4}{ 3} }</u>

<h3><u>v</u><u>)</u><u> </u><u>the</u><u> </u><u>equation</u><u> </u><u>has</u><u> </u><u>two</u><u> </u><u>solu</u><u>tions</u><u>.</u><u> </u><u>write</u><u> </u><u>the</u><u> </u><u>solutions</u><u>,</u><u> </u><u>one</u><u> </u><u>with</u><u> </u><u>a</u><u> </u><u>'</u><u>+</u><u>'</u><u> </u><u>sign</u><u> </u><u>and</u><u> </u><u>anothe</u><u>r</u><u> </u><u>with</u><u> </u><u>a</u><u> </u><u>'</u><u>-</u><u>'</u><u> </u><u>sign</u></h3>

x =  \sqrt{ \frac{4}{3} } \: or \: 1.155

x =  -  \sqrt{ \frac{4}{3} } \:  or - 1.155

<h3 />

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