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rusak2 [61]
2 years ago
5

PLEASE HELP!!! In a large marathon, runners start the race in stages. Sophia started in group E and ran at a rate of 4.8 miles p

er hour. During the race she was passed by Josefina who ran at a rate of 5.3 miles per hour and started in group H, 25 minutes after Sophia started. How far did Sophia run before she was passed by Josefina?
Mathematics
1 answer:
Xelga [282]2 years ago
7 0

Answer:

she ran 1.2 miles

Step-by-step explanation:

take 4.8 and divide it by .25

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Formula to find the missing number Faces:15 vertices:15 edges:?
gtnhenbr [62]

Answer:

Step-by-step explanation:

Euler's formula is

V - E + F = 2

Givens

V = 15

E = 15

F = ?

Solution

15 - 15 + F = 2

F = 2

I'm not sure this makes sense, but it is what the formula gives you.

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3 years ago
Which of the following statements demonstrates the associative property of multiplication?
professor190 [17]
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I hope this helps! 
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2 years ago
How would I calculate the horizontal distance of a parabola?​
maks197457 [2]
X = y2 is the equation for it just plug in the numbers
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1 year ago
HELP PLZZ will give brainliest <3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
3 years ago
Pls help I’ll brainlest ASAP
Dmitry_Shevchenko [17]
Substract by 12 from 42, and keep going down until you hit -54, which is 8 hours!
4 0
2 years ago
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