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denpristay [2]
3 years ago
9

P=$3000,r=9.5%t=9months

Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0
PXrXt /100 is the formula
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Please solve the equation: -2x(-3x2^y)(2y)=?
Blababa [14]

Answer:

6x^2yx2^1+y

Step-by-step explanation:

7 0
2 years ago
A. {0,1,2,3,4}<br> B. {1,2,3,4}<br> C. {-1,0,1,2,3}<br> D. {-2,-1,0,1,2,3,4}
Harlamova29_29 [7]

Option D:

The set is {-2, -1, 0, 1, 2, 3, 4}.

Solution:

Given set:

\{x \in Z:-2 \leq x \leq 4\}

Z means integer values.

Integer means set of positive and negative values including zero.

-2 \leq x \leq 4

This means x lies between -2 and 4.

  • If x strictly less than -2 and greater than 4 means you don't have to include -2 and 4.
  • But here x less than or equal to -2 and greater than or equal to 4, so you have to include -2 and 4.

The integers are -2, -1, 0, 1, 2, 3 and 4.

So, x belongs to the set {-2, -1, 0, 1, 2, 3, 4}

Hence the given set is defined by the set  {-2, -1, 0, 1, 2, 3, 4}.

Option D is the correct answer.

6 0
3 years ago
What is the volume of a sphere with a radius of 6 inches ​
sertanlavr [38]

Answer:

904.78 in I think but I'm not 100%

3 0
3 years ago
Read 2 more answers
Translate the point (5,2)—&gt; 3 units to the left
VladimirAG [237]

Given:

The point (5,-2) is translated 3 units to the left.

To find:

The new location of the point.

Solution:

If a point is translated 3 units to the left, then

(x,y)\to (x-3,y)

Using this rule of translation, we get

(5,-2)\to (5-3,-2)

(5,-2)\to (2,-2)

Therefore, the new location of the point is (2,-2). Hence, the correct option is C.

7 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
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