Answer:
d.
Step-by-step explanation:
if x varies directly as y,
x = ky
8 = 12k
12k = 8
k = 8/ 12
k = 2/3,
x = 2/3 y
now substitute the value of any of the numbers of each pair, and check if it works:
for e.g, find x when y = 15
x = 2/3y
x = 2/3 × 15
x = 10
since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .
ii) x = 2/3y
x = 2/3 × 3, when y = 3
x = 2
hence, this is also a possible pair of x and y values.
iii) x = 2/3y
x = 2/3 × 9 when y = 9
x = 6
again, a possible pair of x and y values.
iv) x = 2/3y
x = 2/3 × 20 when y = 20
x = 40/3
here, when y = 20, x is not 15. it is 40/3.
thus, it can be determined that this is not a possible pair of x and y values.
please try to understand and have a great day!
-3/2 is the factor would multiply the second equation to eliminate y.
The correct option is (C).
<h3>What is factor?</h3>
A number or algebraic expression that divides another number or expression evenly—i.e., with no remainder.
Given equation is :
9x+3/4 y =6
2x+1/2 y =9
If we have to eliminate the y variable so we have to multiply it by factor -3/2
Then the second equation become
-3/2(2x+1/2 y =9)
-3x- 3/4 y =- 27/2
As we can see the y variable of both the equation is same.
Hence, -3/2 is the factor would multiply the second equation to eliminate y.
learn more about this concept here:
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Answer:
Yes
Step-by-step explanation:
Question
1st one RS=DE,
second one T=F,
last one R=D
Answer:
4 bouquets
Step-by-step explanation:
5/5 = 20 flower bouquets.
Find out how much flower bouquets there are when it's 1/5.
5/5 = 20
1/5 = 20 ÷ 5 = 4
Since tulips are 1/5 as 5/5 - 4/5 = 1/5, 4 bouquets are tulips.
