Complete question :
Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?
Answer: Ei = nPi
Step-by-step explanation:
Since Pi represents the probability of observing the ith outcome
The number of independent trials n = k>3 :
Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.
Hence, Expected count (Ei) = probability of ith count * n
Ei = nPi
Answer:
11 $5 dollar bills and 5 one dollar bills.
Step-by-step explanation:
5 times 11 plus 5.
Answer:
C = 50.24
Step-by-step explanation:
C = 2πr
C = 2π(8)
C = 16π
C = 50.24
Tell me if I am wrong.
Can I get brainliest
Okay so 6.5% of $14.95 is 0.97175. That rounds to 0.97. And to get the total we just add 0.97 to 14.95. Our answer is 15.92. However if you don't want to round then you would add 14.95 and 0.97175 . This would give you15.92175. Hope this helps!
Olivia measured to the nearest millimetre because the tenths place value is 0.
