3 years ago

A rectangular prism has a length of 4

Mathematics

1 answer:

telo118 [61]3 years ago

7 0

Answer:

168 units cubed for area

D is your answer

Step-by-step explanation:A=L*W*H

4*3=12*14=168 units cubed

3+45=48*13=624

41*3*11=1353

123*11=1353

12*14=168

You might be interested in

One month, Jon worked 3 hours less than Chaya, and Angelica worked 4 hours more than Chaya. Together they worked 196 hours. Find

OleMash [197]

джон работал на 1 час меньше

3 0

3 years ago

Read 2 more answers

Anybody good at solving solutions?? Need done ASAP

Leto [7]

I am pretty sure that B is the answer

4 0

3 years ago

Astronauts who traveled to the moon were able to float slightly as they walked along its surface. Why wee the astronauts able to

Alex_Xolod [135]

Answer:

Step-by-step explanation:

the farther you get from Earth, the less the gravitational force i, so if your in space, you will have more weight next to earth than you will next to the moon.

7 0

3 years ago

Simplify 3/5-6i A.15+18i/61 B.-15+18i/61 C.3i/6+5i D.15+18i/-11

GrogVix [38]

Answer:

15/61+18/61i

Step-by-step explanation:

6 0

3 years ago

Use the method of reduction of order to find a second independent solution of the given differential equation. t2y'' + 3ty' + y

Charra [1.4K]

I assume you mean $y_1=t^{-1}$ , and not $y_1=t-1$ , since this doesn't satisfy the ODE.

Assume a second solution of the form $y_2=vy_1$ , where $v$ is a function of $t$ . Then

${y_2}'=v'y_1+v{y_1}'$

${y_2}''=v''y_1+2v'{y_1}'+v{y_1}''$

Substituting into the ODE gives

$t^2\left(\dfrac{v''}t-\dfrac{2v'}{t^2}+\dfrac{2v}{t^3}\right)+3t\left(\dfrac{v'}t-\dfrac v{t^2}\right)+\dfrac vt=0$

$\implies tv''+v'=0$

$\implies(tv')'=0$

$\implies tv'=C$

$\implies v'=\dfrac Ct$

$\implies v=C_1\ln|t|+C_2$

$\implies y_2=\dfrac{\ln t}t$

where we omit the second term because it's already accounted for by $y_1$ .

3 0

3 years ago