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alisha [4.7K]
3 years ago
6

A coordinate plane with two polygons is shown. Polygon EFGH has vertices E at 1 comma 1, F at 1 comma 4, G at 5 comma 4, and H a

t 4 comma 1. Polygon E prime F prime G prime H prime has vertices at E prime negative 1 comma 2, F prime negative 4 comma 2, G prime negative 4 comma 6, and H prime at negative 1 comma 5. What set of transformations is performed on EFGH to form E′F′G′H′?
Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0

Answer:

Just here so you can give them brianliest but the answer is B!

Step-by-step explanation:

svetoff [14.1K]3 years ago
4 0

Answer:

B. A translation 1 unit to the right followed by a 90-degree counterclockwise rotation about the origin

Step-by-step explanation:

Polygons EFGH and E′F′G′H′ are shown on the coordinate grid:

What set of transformations is performed on EFGH to form E′F′G′H′?

A. A translation 1 unit to the left followed by a 90-degree counterclockwise rotation about the origin

B. A translation 1 unit to the right followed by a 90-degree counterclockwise rotation about the origin

C. A 90-degree clockwise rotation about the origin followed by a translation 2 units to the right

D. A 90-degree clockwise rotation about the origin followed by a translation 2 units to the left

Answer: Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, dilation and rotation.

If a point X(x, y) is translated a units right and b units up, the new location is (x + a, y + b) also If a point X(x, y) is translated a units left and b units down, the new location is (x - a, y - b)

If a point X(x, y) rotated 90-degree counterclockwise about the origin, the new location is X'(-y, k)

Polygon EFGH has vertices E(1, 1), F(1, 4), G(5, 4), and H(4, 1). If the polygon is translated 1 unit right, the new location is E*(2, 1), F*(2, 4), G*(6, 4) and H*(5, 1).

If it is then rotated 90-degree counterclockwise about the origin, the new location is E'(-1, 2), F'(-4, 2), G'(-4, 6) and H'(-1, 5)

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