Answer:
They cost 730 all together.
Step-by-step explanation:
One the surface area of the hall is 310m^2.
so, 310 divided by 25 is 12.4, which means they need 13 tin of paint.
The cost for it is 13*10 which is 130.
For the area of the floor, it is 40*15, which is 600m^2.
Which costs 600.
So, 600+130=730.
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16
(x^2+10x+16)(x+k)=x^3+9x^2+6x-16
x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16
kx^2+10kx+16k=-x^2-10x-16
k(x^2+10x+16)=-x^2-10x-16
k=(-x^2-10x-16)/(x^2+10x+16)
k=-1
so the width is (x-1)
radius = 3 feet
rearrange the formula making r the subject
πr³ = V ( multiply both sides by 3 to eliminate fraction )
4πr³ = 3V ( divide both sides by 4π )
r³ =
= ( 3 × 36π ) / 4π = 3 × 9 = 27
take the cube root of both sides
r =
= 3
we know that
surface area of the cylinder=2*{area of the base}+perimeter of base*height
area of the base=pi*r²
r=40 ft
Area of base=pi*40²
Area of the base=1600*pi ft²
Perimeter of the base=2*pi*r
Perimeter of the base=2*pi*40
Perimeter of the base=80*pi ft
surface area of the cylinder=2*1600*pi+80*pi*17
surface area=4560*pi ft²
therefore
the answer is the option
4560π ft2
Answer:
A. 15/32 of the writing utensils are black pens