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xxTIMURxx [149]
2 years ago
5

A 1st degree polynomial function whose graph intercepts the y-axis at 8.

Mathematics
1 answer:
asambeis [7]2 years ago
4 0

Your answer can be anything in the form y = mx+8 where you replace m with any real number.

You start with y = mx+b, and then replace the b with the y intercept 8.

The y intercept is where the polynomial crosses the y axis.

The value of m does not matter. So you could have y = 2x+8 or y = 3x+8 for instance. Replace m with whatever your favorite number is.

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PLEASE DO NOT ANSWER THIS EMPTY OR ADD A LINK OR SAY "Answer is in here!" I WILL REPORT YOU IF YOU DO. I DO NOT TAKE FILES PLEAS
Goryan [66]

Answer:

B

M=2

Step-by-step explanation:

rise over run

you rise 2 and go over 1

2 over 1 is just 2.

3 0
3 years ago
Read 2 more answers
Describe a real world situauationthat could be modled by dividing two rational numbers
Dima020 [189]
You have 10 slices of cake, you and your friends Jerry, George, Martha, and Jenny ( just an example ) eat 2 slices of cake. 
A more real life one would be:
You have 6 bills to pay off, then two more come in, you only pay off 4, 
( I hope this helped, I'm sorry if any of this is wrong:) )
7 0
3 years ago
What’s the answer for number 7????????????
kodGreya [7K]

Choice C, because

\frac{3}{4}  =  \frac{6}{8}

So it's less than what she originally had (which isn't possible)

6 0
3 years ago
A team has 3 wins for every loss they loss games how many did they win??
OLEGan [10]
The team has lost only 6 games (according to the comments). Let's say "x" is the amount of losses and "y" is the amount of wins.

For every loss, they have 3 wins, so in the end, this would be the equation:
y = 3x
or
y = 3 \times x
Although the first one would be the easier and most understandable to read.

So:
y = 3(6)
would equal
18
5 0
3 years ago
Find the equation (in terms of x ) of the line through the points (-2,5) and (3,4)<br> y=
Alja [10]

Answer:

y = (-1/5)x + 23/5

Step-by-step explanation:

Given:

Two points;

(-2,5) and (3,4)

Find:

Equation of slope

Computation:

y = mx + b

5 = m(-2) + b

5 = -2m + b .......... Eq1

4 = m(3) + b

4 = 3m + b .......... Eq2

Eq2 - Eq1

-1 = 5m

m = -1/5

5 = -2m + b

5 = -2(-1/5) + b

5 = 2/5 + b

b = 23/5

y = mx + b

y = (-1/5)x + 23/5

3 0
3 years ago
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